Question

def function():

    import pygame
    import time
    from pygame.locals import *

    pygame.init()

    Width = 272
    Height = 552

    white = 255,255,255
    blue = 0,255,255
    red = 255,0,0

    Left_Rect = pygame.Rect(0,452,135,100)
    Right_Rect = pygame.Rect(137,452,135,100)

    Location = 136

    WaterLevel = 452
    Depth = 100

    CLOCK = pygame.time.Clock()
    FPS = 30

    gameDisplay = pygame.display.set_mode((Width,Height))
    pygame.display.set_caption('boat game')

    stop = False

    gameDisplay.fill(white)

    while not stop:

####### CONTROLLES ####################################################

        pygame.draw.rect(gameDisplay, red, Left_Rect)

        pygame.draw.rect(gameDisplay, red, Right_Rect)


####### BOAT #########################################################
        pygame.draw.rect(gameDisplay, red, (Location,WaterLevel-20,40,20))

####### WATER ########################################################        
        pygame.draw.rect(gameDisplay,blue,(0,WaterLevel,272,Depth))

        WaterLevel -= 1
        Depth += 1


######################################################################

        for event in pygame.event.get():

            print event

            if event.type == pygame.MOUSEBUTTONDOWN:
                is_Left = Left_Rect.collidepoint(pygame.mouse.get_pos())

                if is_Left == 1:
                    Location -= 5

            if event.type == pygame.MOUSEBUTTONDOWN:
                is_Right = Right_Rect.collidepoint(pygame.mouse.get_pos())

                if is_Right == 1:
                    Location += 5

            if event.type == pygame.QUIT:
                stop = True
                pygame.quit()
                quit()

        CLOCK.tick(FPS)

        pygame.display.update()

function()

我有一个蓝色的矩形从屏幕上升起，一个红色的矩形位于上升的蓝色矩形的顶部。在左下角和右下角放置两个盒子，当它们被点击时，红色盒子向左或向右水平移动。我怎样才能做到这一点，所以我可以将鼠标放在其中一个盒子上，矩形将继续移动直到我放开

Answer 1

该问题有许多不同的方法。：）

非常简单快捷的方法

is_Left

设置两个全局变量之一is_Right和pygame.MOUSEBUTTONDOWN 和各自的{{ 1}}方法返回.collidepoint()

true

重置两个变量。

此方法的更新代码：

pygame.MOUSEBUTTONUP

正如Marius已经提到的，另一种方法是使用PyGames鼠标模块的pygame.mouse.get_pressed()函数来获取鼠标按钮的状态。

此函数返回三个布尔值的#your original code #declare global variables is_Left and is_Right is_Left = False is_Right = False while not stop: #draw controls, boat and water #increment WaterLevel and Depth #event loop for event in pygame.event.get(): #detect MOUSEBUTTONDOWN event and collision if event.type == pygame.MOUSEBUTTONDOWN: is_Left = Left_Rect.collidepoint(pygame.mouse.get_pos()) is_Right = Right_Rect.collidepoint(pygame.mouse.get_pos()) if event.type == pygame.MOUSEBUTTONUP: #reset is_Left and is_Right is_Left = False is_Right = False if event.type == pygame.QUIT: pygame.quit() quit() #change Location if is_Left: Location -= 5 elif is_Right: Location += 5 CLOCK.tick(FPS) pygame.display.update()，表示所有鼠标按钮的状态。在您的情况下，我们只需要第一个值，它代表鼠标左键的状态。

我们在主游戏循环中调用tupel 以获取鼠标左键的状态，并同时检查相应的{{1} }}方法返回pygame.mouse.get_pressed()[0]：

.collidepoint()

个人更喜欢第二个变体，因为我们不需要任何额外的全局变量（true，#your original code while not stop: #draw controls, boat and water #increment WaterLevel and Depth #event loop for event in pygame.event.get(): if event.type == pygame.QUIT: pygame.quit() quit() #get state of left mouse button isPressed = pygame.mouse.get_pressed()[0] #change location if ispressed and Left_Rect.collidepoint(pygame.mouse.get_pos()): Location -= 5 elif ispressed and Right_Rect.collidepoint(pygame.mouse.get_pos()): Location += 5 CLOCK.tick(FPS) pygame.display.update() CLOCK.tick(FPS) pygame.display.update()）。

我希望这会有所帮助：）

如何在pygame中获得连续运动？

1 个答案: