Question

我在将数据插入sqlite数据库时遇到问题。

    char *update="INSERT OR REPLACE INTO ct_subject (id,id_parent, title, description, link, address, phone, pos_lat, pos_long, no_votes, avg_vote, photo, id_comerc, id_city, placement, type, timestamp, mail) VALUES (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?);";
        sqlite3_stmt *stmt;
        if(sqlite3_prepare_v2(database, update, -1, &stmt, nil) == SQLITE_OK){
            sqlite3_bind_int(stmt, 1, [[[newCategories objectAtIndex:i] valueForKey:@"id"] intValue]);
            sqlite3_bind_int(stmt, 2, [[[newCategories objectAtIndex:i] valueForKey:@"id_parent"] intValue]);
            sqlite3_bind_text(stmt, 3, [[[newCategories objectAtIndex:i] valueForKey:@"title"] UTF8String], -1, NULL);
            sqlite3_bind_text(stmt, 4, [[[newCategories objectAtIndex:i] valueForKey:@"description"] UTF8String], -1, NULL);
            sqlite3_bind_text(stmt, 5, [[[newCategories objectAtIndex:i] valueForKey:@"link"] UTF8String], -1, NULL);
            sqlite3_bind_text(stmt, 6, [[[newCategories objectAtIndex:i] valueForKey:@"address"] UTF8String], -1, NULL);
            sqlite3_bind_text(stmt, 7, [[[newCategories objectAtIndex:i] valueForKey:@"phone"] UTF8String], -1, NULL);
            sqlite3_bind_text(stmt, 8, [[[newCategories objectAtIndex:i] valueForKey:@"pos_lat"] UTF8String], -1, NULL);
            sqlite3_bind_text(stmt, 9, [[[newCategories objectAtIndex:i] valueForKey:@"pos_long"] UTF8String], -1, NULL);
            sqlite3_bind_int(stmt, 10, [[[newCategories objectAtIndex:i] valueForKey:@"no_votes"] intValue]);
            sqlite3_bind_text(stmt, 11, [[[newCategories objectAtIndex:i] valueForKey:@"avg_vote"] UTF8String], -1, NULL);
            if ([[[newCategories objectAtIndex:i] valueForKey:@"photo"] length]!=0) {
                NSMutableString *webUrl = (NSMutableString *)[[NSMutableString alloc] initWithString:@"http://www.crotune.com/public/images/subjects/"];
                [webUrl appendString:[[newCategories objectAtIndex:i] valueForKey:@"photo"]];
                UIImage *myImage =  [self getWebImage:webUrl]; 
                if(myImage != nil){
                    sqlite3_bind_blob(stmt, 12, [UIImagePNGRepresentation(myImage) bytes], [UIImagePNGRepresentation(myImage) length], NULL);
                }
                else {
                    sqlite3_bind_blob(stmt, 12, nil, -1, NULL);
                }
                [webUrl release];
                [myImage release];
            }
            else {
                sqlite3_bind_blob(stmt, 12, nil, -1, NULL);
                    //NSLog(@" ne dodajem sliku2");
            }

            sqlite3_bind_int(stmt, 13, [[[newCategories objectAtIndex:i] valueForKey:@"id_comerc"] intValue]);
            sqlite3_bind_int(stmt, 14, [[[newCategories objectAtIndex:i] valueForKey:@"id_city"] intValue]);
            sqlite3_bind_int(stmt, 15, [[[newCategories objectAtIndex:i] valueForKey:@"placement"] intValue]);
            sqlite3_bind_int(stmt, 16, [[[newCategories objectAtIndex:i] valueForKey:@"type"] intValue]);
            sqlite3_bind_int(stmt, 17, [[[newCategories objectAtIndex:i] valueForKey:@"timestamp"] intValue]);
            sqlite3_bind_text(stmt, 18, [[[newCategories objectAtIndex:i] valueForKey:@"mail"] UTF8String], -1, NULL);
        }
        if (sqlite3_step(stmt) != SQLITE_DONE) {
            NSLog(@"%s", sqlite3_errmsg(database));
            NSAssert1(0,@"nemogu updateat table %s", errorMsg);
        }
        else {
                NSLog(@"Ubacio %d",i);
        }sqlite3_finalize(stmt);

它会开始吃内存，直到最终退出...在内存警告我再次关闭并打开数据库时，我已将缓存大小设置为50，如此处的一些帖子所述，并尝试将查询置于语句中 - 相同的结果.. 在iphone上插入300个插件或在iPad上插入约900个插件后，它只会让妈咪和应用程序退出... 任何帮助将不胜感激..

Answer 1

哇。与CoreData相比，SQLite代码很难看。但是，嘿，他自己......

使用Allocations工具找出消耗所有内存的内容。在没有看到代码的情况下，UIImage *myImage = [self getWebImage:webUrl];可能会过度保留图像数据吗？

除此之外，如果没有看到更多代码或更多证据，很难猜测可能会发生什么。

在插入时，iPhone上的sqlite eatup内存

1 个答案: