如何使Parse Queries不同，以便它们不会相互影响？

Question

如何隔离Parse查询以使其不会影响其他查询？现在我的代码看起来像：

query.include("thing");
query.find({
     success: function(results){
     //there are results here as expected
     }
})

query2.doesNotExist("something");
query2.find({
      success: function(items){
      //there are items here as expected
     }
})


query.exists("key");
query.find({
     success: function(keys){
     //there are no results here but if I reverse the order of the queries . . .
     }
})

现在，如果我以不同的顺序放置这些查询，我将最后一个查询放在上面，我得到了预期的结果。

query.exists("key");
query.find({
     success: function(keys){
     //there are no results here but if I reverse the order of the queries . . .
     }
})


query.include("thing");
query.find({
     success: function(results){
     //there are results here as expected
     }
})

query2.doesNotExist("something");
query2.find({
      success: function(items){
      //there are items here as expected
     }
})

似乎两个Parse Queries用于查询＆＃39;相互影响。我如何解决这个问题，以便每个查询都是独特的？

Answer 1

经过进一步调查后，您似乎无法在Parse中继续查询。但是，您可以在同一个表/集合上创建新的Parse.Query。