我正在尝试创建d3堆积条形图。数据格式如下
var dataset = [{
"effort": "initial",
"co": [{
"number": "123",
"act_effort": 10
},{
"number": "456",
"act_effort": 10
}, {
"number": "678",
"act_effort": 0
}]
}, {
"effort": "scope_creep",
"co": [{
"number": "456",
"act_effort": 5
}, {
"number": "123",
"act_effort": 0
}, {
"number": "678",
"act_effort": 15
}]
},{
"effort": "qc_support",
"co": [{
"number": "456",
"act_effort": 5
},{
"number": "678",
"act_effort": 15
}, {
"number": "123",
"act_effort": 5
}]
}, {
"effort": "uat_support",
"co": [{
"number": "456",
"act_effort": 0
}, {
"number": "678",
"act_effort": 15
},{
"number": "123",
"act_effort": 0
}]
}];
由于数据未排序,我的堆积栏中的栏之间会有中断。
如果我将数据更改为下面的数据
var dataset = [{
"effort": "initial",
"co": [{
"number": "123",
"act_effort": 10
},{
"number": "456",
"act_effort": 10
}, {
"number": "678",
"act_effort": 0
}]
}, {
"effort": "scope_creep",
"co": [
{
"number": "123",
"act_effort": 0
},{
"number": "456",
"act_effort": 5
}, {
"number": "678",
"act_effort": 15
}]
},{
"effort": "qc_support",
"co": [{
"number": "123",
"act_effort": 5
},{
"number": "456",
"act_effort": 5
},{
"number": "678",
"act_effort": 15
}]
},{
"effort": "uat_support",
"co": [{
"number": "456",
"act_effort": 0
}, {
"number": "678",
"act_effort": 15
},{
"number": "123",
"act_effort": 0
}]
}];
这是工作jsfiddle
我尝试使用d3.sort()函数没有运气。
dataset = dataset.sort(function(a,b) { return d3.ascending(a.y, b.y); }
有人可以建议我如何实现这一目标吗?提前谢谢。
答案 0 :(得分:1)
尝试按如下所示对数据进行排序。
var dataset = dataset.map(function (d) {
var sortedData = d.co.sort(function(a,b){ return d3.ascending(a.number, b.number); });
return sortedData.map(function (o, i) {
return {
y: o.act_effort,
x: o.number
};
});
});
var dataset = [{
"effort": "initial",
"co": [{
"number": "123",
"act_effort": 10
},{
"number": "456",
"act_effort": 10
}, {
"number": "678",
"act_effort": 0
}]
}, {
"effort": "scope_creep",
"co": [{
"number": "456",
"act_effort": 5
}, {
"number": "123",
"act_effort": 0
}, {
"number": "678",
"act_effort": 15
}]
},{
"effort": "qc_support",
"co": [{
"number": "456",
"act_effort": 5
},{
"number": "678",
"act_effort": 15
}, {
"number": "123",
"act_effort": 5
}]
}, {
"effort": "uat_support",
"co": [{
"number": "456",
"act_effort": 0
}, {
"number": "678",
"act_effort": 15
},{
"number": "123",
"act_effort": 0
}]
}];
var margin = {
top: 50,
right: 30,
bottom: 50,
left: 50
},
lagendPanel = {
width: 180
},
width = 960 - margin.left - margin.right - lagendPanel.width,
height = 500 - margin.top - margin.bottom;
var barPadding = 2;
d3.select("#main")
.append("h4")
.text("CO v/s Actual Effort Graph");
var effortTyp = dataset.map(function (d) {
return d.effort;
});
var dataset = dataset.map(function (d) {
var sortedData = d.co.sort(function(a,b){ return d3.ascending(a.number, b.number); });
return sortedData.map(function (o, i) {
// Structure it so that your numeric
// axis (the stacked amount) is y
return {
y: o.act_effort,
x: o.number
};
});
});
console.log(dataset);
var stack = d3.layout.stack();
stack(dataset);
var dataset = dataset.map(function (group) {
return group.map(function (d) {
// Invert the x and y values, and y0 becomes x0
return {
x: d.y,
y: d.x,
x0: d.y0
};
});
});
console.log(dataset);
var svg = d3.select("#main")
.append('svg')
.attr("width", width + (2 * margin.left) + margin.right + lagendPanel.width)
.attr('height', height + margin.top + margin.bottom)
.append('g')
.attr('transform', 'translate(' + margin.left + ',' + margin.top + ')');
var xMax = d3.max(dataset, function (group) {
return d3.max(group, function (d) {
return d.x + d.x0;
});
});
var xScale = d3.scale.linear()
.domain([0, xMax])
.range([0, width]);
var numbers = "";
numbers = dataset[0].map(function (d) {
console.log(d.y);
return d.y;
});
var yScale = d3.scale.ordinal()
.domain(numbers)
.rangeRoundBands([0, height], .1);
//Axis
var xAxis = d3.svg.axis()
.scale(xScale)
.orient('bottom'),
yAxis = d3.svg.axis()
.scale(yScale)
.orient('left'),
colours = d3.scale.category10();
var groups = svg.selectAll('g')
.data(dataset)
.enter()
.append('g')
.style('fill', function (d, i) {
return colours(i);
}),
rects = groups.selectAll('rect')
.data(function (d) {
return d;
})
.enter()
.append('rect')
.attr('x', function (d) {
return xScale(d.x0);
})
.attr('y', function (d, i) {
return yScale(d.y);
})
.attr('height', function (d) {
return yScale.rangeBand();
})
.attr('width', function (d) {
return xScale(d.x);
});
svg.append('g')
.attr('class', 'axis')
.attr('transform', 'translate(0,' + height + ')')
.call(xAxis);
svg.append('g')
.attr('class', 'axis')
.call(yAxis);
svg.append('g')
.attr('class', 'axis')
.call(yAxis);
svg.append('rect')
.attr('fill', 'yellow')
.attr('width', 160)
.attr('height', 30 * dataset.length)
.attr('x', width + margin.left)
.attr('y', 0);
effortTyp.forEach(function (s, i) {
svg.append('text')
.attr('fill', 'black')
.attr('x', width + margin.left + 8)
.attr('y', i * 24 + 24)
.text(s);
svg.append('rect')
.attr('fill', colours(i))
.attr('width', 60)
.attr('height', 20)
.attr('x', width + margin.left + 90)
.attr('y', i * 24 + 6);
});

<script type="text/javascript" src="http://d3js.org/d3.v3.min.js"></script>
<div id="main"></div>
&#13;
答案 1 :(得分:0)
我为你的d.co.map
添加了一个排序,似乎已经完成了这个伎俩:
var dataset = dataset.map(function (d) {
return d.co.map(function (o, i) {
// Structure it so that your numeric
// axis (the stacked amount) is y
return {
y: o.act_effort,
x: o.number
};
}).sort(function(a, b) {
return d3.ascending(parseInt(a.x), parseInt(b.x));
});
});
Here是一个更新的工作jsfiddle。