$query = mysql_query("SELECT Name from lottery");
// Make All Lotteries Into An Array
$queryarray = mysql_fetch_array($query);
// For Each Lottery, Store the Name of It in $lottery
foreach ($queryarray as $lottery) {
// Select IDs of Tickets in Current Selected Lottery ($lottery)
$ticketquery = mysql_query("SELECT id FROM tickets WHERE lottery='$lottery'");
// Create an Array from the IDS
$ticketarray = mysql_fetch_assoc($ticketquery);
// Select A Random ID, This Is Our Winner Ticket
$winner = $ticketarray[array_rand($ticketarray)];
}
然而,当我运行它时,我收到此错误:
mysql_fetch_assoc
替换为mysql_fetch_array
,但这也没有多大帮助。刚给我同样的错误。有任何想法吗?谢谢。
第25行:$winner = $ticketarray[array_rand($ticketarray)];
答案 0 :(得分:1)
将代码编写为:
while($lottery = mysql_fetch_array($query)){...}
可以解决问题。