在python中将列表拆分为数组

Question

我有一个问题要将数组拆分成数组，这里是源代码和输出，

import numpy as np

s = np.array([[100], [200], [300], [400], [500]])
mean = np.mean(s)
stdev = s.std()
for i in range(len(s)):
    z = ((s[i]-mean)/stdev)
    print z

out：

[-1.41421356]
[-0.70710678]
[ 0.]
[ 0.70710678]
[ 1.41421356]

我希望输出如下：

[[-1.41421356]
[-0.70710678]
[ 0.]
[ 0.70710678]
[ 1.41421356]]

Answer 1

创建一个空列表，然后将结果追加到该空列表中。

import numpy as np
s = np.array([[100], [200], [300], [400], [500]])
mean = np.mean(s)
stdev = s.std()
x = []
for i in range(len(s)):
    x.append(((s[i]-mean)/stdev))
print np.array(x)

Answer 2

试试这个

...
...
z = []

for i in range(len(s)):

    z.append((s[i]-mean)/stdev)

print z