您好我有一个完全运行的短信应用程序,它执行发送和接收的双向过程。我现在发送收到的短信。 我只是保证我收到短信,所以只是显示分裂部分的代码。
'Split parts of the Message Received by "_"
Dim textmess As String() = Message.Split("_")
Dim pass As String = textmess(0)
Dim txt As String = textmess(1)
Dim recipients As String = textmess(2)
我使用拆分功能将消息分成3部分。如果消息显示“abc_123_432”,那么pass,txt,收件人将分别拥有abc,123,432但已分开。
'Verify Number for Authorization
myr.Close()
mycom.Connection = cn
mycom.CommandText = "Select MobileNum,Name,UserName,Password,Position from tbl_user where MobileNum='" & Number1 & "'"
myr = mycom.ExecuteReader()
If myr.Read Then
Dim num As String = myr(0).ToString
Dim name As String = myr(1).ToString
Dim user As String = myr(2).ToString
Dim pass2 As String = myr(3).ToString
Dim post As String = myr(4).ToString
If num = Number1 Then
myr.Close()
mycom.CommandText = "Insert into tbl_inbox(message,received_date,sender) values ('" & Message & "','" & DateAndTime.Now.ToString & "','" & name & "');"
myr = mycom.ExecuteReader
myr.Close()
我只想指定当我向我的应用程序发送短信时,它超过了这部分,因为当我检查我的收件箱表时,它会显示我发送的正确消息。在下面的代码中,我不知道那里出了什么问题。
If pass2 = pass1 Then
mycom.CommandText = "Insert into tbl_activity(UserName,Activity,CDate) values ('" & user & "','Send SMS to System','" & DateAndTime.Now.ToString & "');"
myr = mycom.ExecuteReader
Form1.txtnumber.Text = recipients
Form1.txtmessage.Text = txt
Form1.btnSend.PerformClick()
Else
MessageBox.Show(pass1)
MessageBox.Show(txt)
MessageBox.Show(recipients)
End If
End If
End If
myr.Close()
End If
我还尝试在比较之前使pass1和pass2出现在消息框中,但即使它们完全相同,它仍然不会通过。请帮助我们,我只需要尽快获得所需的代码,谢谢
答案 0 :(得分:0)
更改
Dim textmess As String() = Message.Split("_")
到
Dim textmess As String() = Split(Message,"_")
为什么你在比较STRINGS时使用= ??? 试试这个:
If pass2.equals(pass1) Then