Question

我有一个应用程序，在第一页上，用户可以看到四种产品供他选择。保存数据后，我将显示所有四种产品的列表，并在用户选择的产品旁边放置“check”。我的逻辑有问题 - 有人可以帮忙吗？

// user can choose from these products
$products = array(
    '1'=>'Product One',
    '2'=>'Product Two',
    '3'=>'Product Three',
    '4'=>'Product Four' );

// user has choosen these products
$selected_products = explode(',', 'Product One,Product Four');
foreach($selected_products as $product)
{
    // Have to print out all products from $products variable, and check 
    // the ones that the user selected from the $selected_products string.
}

Answer 1

请确保所选产品作为ID而不是产品名称返回。然后，您可以使用in_array()来确定是否应选中复选框。

<?php

$products = array(1=>'Product One', 2=>'Product Two', 3=>'Product Three', 4=>'Product Four');
$selectedProducts = array(1,4);

foreach($products as $key => $value) {
    $checked = in_array($key, $selectedProducts) ? ' checked' : '';
    echo '<input type="checkbox" id="product'.$key.'" value="'.$key.'"'.$checked.' /> <label for="product'.$key.'">'.$value.'</label>';
}

Answer 2

您可以使用in_array()检查它是否是所选值中的已检查选项之一。粗略的例子：

$products = array('1'=>'Product One','2'=>'Product Two','3'=>'Product Three','4'=>'Product Four');
// user has choosen these products
$selected_products = explode(',', 'Product One,Product Four');
foreach($products as $id => $p) {
    $checked = (in_array($p, $selected_products)) ? 'checked' : '';
    echo "<input type='checkbox' name='check' value='{$id}' $checked /> {$p}<br/>";
}

Answer 3

$products = array('1'=>'Product One','2'=>'Product Two','3'=>'Product Three','4'=>'Product Four');
// user has choosen these products
$selected_products = explode(',', 'Product One,Product Four');
foreach($products as $id => $p) {
    $checked = (in_array($p, $selected_products)) ? 'checked' : '';
    echo "<input type='checkbox' name='check' value='{$id}' $checked /> {$p}<br/>";
}

如何从用户选择的值生成一个复选框

3 个答案: