我有这张桌子:
Player Routes Colors
GIN 2 RED
GIN 1 BLU
GIN 5 BLAS
GIN 1 TREN
GIN 2 RED
PON 1 TREN
PON 4 BLU
来自带有union all的查询的,如下所示:
select *
from (
select DISTINCT Colors.Name [Colors]
, COUNT(routes.idRoutes) [Routes]
, Routes.cdRoutes [Doc]
from Routes
inner join Colors on Colors.Name blablabla
where blablabla
group by Colors.Name, Routes.cdRoutes
) dates
我需要有一个这样的表:
Colors GIN PON
RED 4 0
BLU 1 4
BLAS 5 0
TREN 1 1
怎么样?我想我可以在不使用PIVOT功能的情况下获得它,对吗?
答案 0 :(得分:1)
你可以这样做(即使不使用PIVOT):
select
Colors,
sum(case when Player = 'GIN' then Routes else 0 end) as GIN,
sum(case when Player = 'PON' then Routes else 0 end) as PON
from your_query_or_Table
group by Colors