我无法让以下工作：
$stmt = $mysqli->prepare("INSERT INTO member_data (member_id, name, address, telephone, mobile) VALUES (?, ?, ?, ?, ?) ON DUPLICATE KEY UPDATE member_data SET name = ?, address = ?, telephone = ?, mobile = ? WHERE member_id = ?");
$stmt->bind_param('ssssssssss', $_SESSION['user_id'], $_POST['new_name'], $_POST['new_address'], $_POST['new_telephone'], $_POST['new_mobile'], $_POST['new_name'], $_POST['new_address'], $_POST['new_telephone'], $_POST['new_mobile'], $_SESSION['user_id']);
$stmt->execute();
$stmt->close();
它似乎无法更新或插入任何值。
我确定我做错了什么，但我已经搜索过，并且找不到与我的问题相关的任何内容。这是正确的做法吗？
编辑：工作代码：
$stmt = $mysqli->prepare("INSERT INTO member_data (member_id, name, address, telephone, mobile) VALUES (?, ?, ?, ?, ?) ON DUPLICATE KEY UPDATE name = ?, address = ?, telephone = ?, mobile = ?");
$stmt->bind_param('sssssssss', $_SESSION['user_id'], $_POST['new_name'], $_POST['new_address'], $_POST['new_telephone'], $_POST['new_mobile'], $_POST['new_name'], $_POST['new_address'], $_POST['new_telephone'], $_POST['new_mobile']);