使用Fluent Assertions我们可以使用以下内容断言两个集合是相等的(在属性值方面):
list1.ShouldBeEquivalentTo(list2);
假设list1
和list2
包含相同的对象in any order
,则断言将为真。
如果我们想要按照确切的顺序断言列表,我们可以这样做:
list1.ShouldBeEquivalentTo(list2, o => o.WithStrictOrdering());
如果列表在wrong order
中包含相同的对象但我无法找到任何内容,那么我正在寻找断言为假的内容。
使用Fluent断言的最佳方法是什么?
PS - 它是一种学术上的好奇心,在现实中甚至可能没那么有用:)答案 0 :(得分:1)
编辑:现在我了解戴维要求的内容(请参阅下面的评论)我将代码更新为此解决方案。虽然语法类似,但它不是FluentAssertion扩展,但可能有一些操作。
public static class IEnumerableAssertionExtensions
{
public static void ShouldContainInWrongOrder<TSubject>(this IEnumerable<TSubject> source, IEnumerable<TSubject> expected)
{
var remaining = expected.ToList();
var inOrder = true;
foreach (var subject in source)
{
if (inOrder && !ReferenceEquals(subject, remaining[0]))
{
inOrder = false;
}
var s = subject;
Execute.Verification.ForCondition(() => remaining.Remove(s)).FailWith("Expected item in the collection: {0}", subject.ToString());
}
Execute.Verification.ForCondition(() => remaining.Count == 0).FailWith(string.Format("{0} more item{1} than expected found in the list.", remaining.Count, ((remaining.Count == 1) ? string.Empty : "s")));
Execute.Verification.ForCondition(() => !inOrder).FailWith("list items are ordered identically");
}
}
[TestClass]
public class TestFoo
{
class Thing
{
public int i;
}
[TestMethod]
public void MyMethod()
{
var a1 = new Thing { i=0 };
var a2 = new Thing { i=1 };
var a3 = new Thing { i=2 };
var a4 = new Thing { i=2 };
var list1 = new List<Thing> { a1, a2, a3 };
var list2 = new List<Thing> { a1, a2, a3 };
var list3 = new List<Thing> { a3, a2, a1 };
var list4 = new List<Thing> { a1, a2, a3, a4 };
var list5 = new List<Thing> { a3, a2 };
list1.ShouldContainInWrongOrder(list3); // Succeeds
list1.ShouldContainInWrongOrder(list2); // Fails
list1.ShouldContainInWrongOrder(list4); // Fails
list1.ShouldContainInWrongOrder(list5); // Fails
}
}