Question

我尝试在我的项目中创建一个新的数据库，但是当我运行脚本时遇到了这个错误，我有另一个使用类似定义的项目，它之前有效，但现在它得到了同样的错误。我使用的是Python 2.7.8，SQLAlchemy模块的版本是0.9.8。顺便说一句，一个项目使用Flask-SQLAlchemy，它运行良好。我很迷惑。回溯信息如下：

Traceback (most recent call last):
  File "D:/Projects/OO-IM/db_create.py", line 4, in <module>
    from models import Base
  File "D:\Projects\OO-IM\models.py", line 15, in <module>
    Column('followed_id', Integer(), ForeignKey('user.id'))
  File "C:\Python27\lib\site-packages\sqlalchemy\sql\schema.py", line 369, in __new__
    schema = metadata.schema
  File "C:\Python27\lib\site-packages\sqlalchemy\sql\elements.py", line 662, in __getattr__
    key)
AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema'


from sqlalchemy import create_engine, Column, String, Integer, Text, DateTime, Boolean, ForeignKey, Table
from sqlalchemy.orm import sessionmaker, relationship, backref
from sqlalchemy.ext.declarative import declarative_base

SQLALCHEMY_DATABASE_URI = "mysql://root:mysqladmin@localhost:3306/oo_im?charset=utf8"

Base = declarative_base()

# TODO:AttributeError: Neither 'Column' object nor 'Comparator' object has an attribute 'schema'
friendships = Table('friendships',
                    Column('follower_id', Integer(), ForeignKey('user.id')),
                    Column('followed_id', Integer(), ForeignKey('user.id'))
)


class User(Base):
    __tablename__ = 'user'
    id = Column(Integer(), primary_key=True)
    account = Column(String(32), unique=True, nullable=False)
    password = Column(String(32), nullable=False)
    followed = relationship("User",
                            secondary=friendships,
                            primaryjoin=(friendships.c.follower_id == id),
                            secondaryjoin=(friendships.c.followed_id == id),
                            backref=backref("followers", lazy="dynamic"),
                            lazy="dynamic")

    def __init__(self, account, password, followed=None):
        self.account = account
        self.password = password

        if followed:
            for user in followed:
                self.follow(user)

    def follow(self, user):
        if not self.is_following(user):
            self.followed.append(user)
            return self

    def unfollow(self, user):
        if self.is_following(user):
            self.followed.remove(user)
            return self

    def is_following(self, user):
        return self.followed.filter(friendships.c.followed_id == user.id).count() > 0


class ChatLog(Base):
    __tablename__ = 'chatlog'
    id = Column(Integer(), primary_key=True)
    sender_id = Column(Integer(), ForeignKey('user.id'), nullable=False)
    receiver_id = Column(Integer(), ForeignKey('user.id'), nullable=False)
    send_time = Column(DateTime(), nullable=False)
    received = Column(Boolean(), default=False)
    content = Column(Text(), nullable=False)


engine = create_engine(SQLALCHEMY_DATABASE_URI, convert_unicode=True)
DBSession = sessionmaker(bind=engine)

Answer 1

表定义应为：

friendships = Table('friendships',
                    Base.metadata,
                    Column('follower_id', Integer(), ForeignKey('user.id')),
                    Column('followed_id', Integer(), ForeignKey('user.id'))
)

使用声明性语法定义表时，元数据通过Base的类声明继承，即

Base = declarative_base()

class ChatLog(Base)

但是，在使用旧的Table语法定义表时，必须明确指定元数据。

Answer 2

我遇到了同样的错误，因为我使用小写Column拼写c。它应该是Column。

Answer 3

我遇到了类似的问题。准确地说，我面临的错误是： AttributeError: Neither 'ColumnClause' object nor 'Comparator' object has an attribute '_set_parent_with_dispatch'

经过一番挣扎，我发现这是一个拼写错误。我在下面的代码段第 6 行中将 sa.Column 拼写为 sa.column。

from alembic import op
import sqlalchemy as sa

def something():
    op.add_column('table_name',
        sa.Column('column_name', sa.Text(), nullable=True) # Correct usage
    )

Python SQLAlchemy：AttributeError：No＆＃39; Column＆＃39;对象也不是＆＃39;比较器＆＃39;对象具有属性＆＃39; schema＆＃39;

3 个答案: