解析int时eclipse中的java.lang.NumberFormatException错误

时间:2015-03-25 00:31:19

标签: java parsing sorting stopwatch seed

我试图使用秒表类来测量我的代码在ArrayList和LinkedList上运行的速度。当我尝试编译代码时,我继续收到此错误。

Exception in thread "main" java.lang.NumberFormatException: For input string: "java"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at SortTest.main(SortTest.java:10)

我的代码如下所示:

import java.util.ArrayList;
import java.util.Collections;
import java.util.Random;


public class SortTest {

public static void main(String[] args) {

    final int N = Integer.parseInt(args[0]);
    ArrayList<Integer> thelist = new ArrayList();
    int x = 1;
    while (x < N) {
        thelist.add(x);
    }

    final Random RNG = new Random (Long.getLong("seed", System.nanoTime()));
    Collections.shuffle(thelist, RNG);

    /////////////
    //STOPWATCH//
    /////////////

    final StopWatch sw = new StopWatch(true);
    for (int i = 0; i < 25; i++) {
        sw.start();

        int smaller = 0;
        int smallerindex = 0;
        int b = 0;
        for(int a = 1; a <thelist.size(); a++) {
            smaller = thelist.get(a - 1);
            smallerindex = a - 1;
            for(b = a; b <thelist.size(); b++) {
                if(thelist.get(b) < smaller) {
                    smaller = thelist.get(b);
                    smallerindex = b;
                }
            }
            if (smallerindex ==  a) {
                //no action
            } else {
            int temp = thelist.get(a);
            thelist.set(a, thelist.get(smallerindex));
            thelist.set(smallerindex, temp);
            }  
        }

        sw.stop();
    }
    final double averageTime = sw.getAverageTime();

    System.out.println(averageTime);
}
}

我的命令行输入如下所示:

java -Dseed=4321567 SortTest 200 java.util.ArrayList

我尝试将N初始化为0和1,并且错误已经不存在了。一旦我将N设置为2,错误就会恢复。所以我从中得到的是N&gt;的问题。但我不知道究竟是什么导致了这个错误。帮助将不胜感激。

1 个答案:

答案 0 :(得分:2)

为什么不自己尝试调试呢。这是你如何开始的。

for(int i = 0; i < args.length; i++){
  System.out.println("Arg "+i+" is: "+args[i]);
}