Php正则表达式:从查询字符串中删除顺序

时间:2015-03-24 11:28:05

标签: php regex

我有一个php方法,它应该删除"命令的所有出现。来自mysql查询字符串的mysql语句。

示例1:

STRING:SELECT * FROM table ORDER BY name

结果:SELECT * FROM table

示例2:

STRING:SELECT a.* FROM (SELECT * FROM table ORDER BY name, creation_date) AS a ORDER BY a.name

结果:SELECT a.* FROM (SELECT * FROM table) AS a

我现在的问题是:如何实现这个目标。

我尝试了以下内容:

if (stripos($sql, 'ORDER BY') !== false) {
    $sql = preg_replace('/\sORDER\ BY.+/i', '', $sql);
}

但这适用于示例1,但不适用于示例2

2 个答案:

答案 0 :(得分:3)

您可以使用的正则表达式为ORDER BY.*?(?=\s*LIMIT|\)|$)

示例代码:

$re = "/ORDER BY.*?(?=\\s*LIMIT|\\)|$)/mi"; 
$str = "SELECT * FROM table ORDER BY name\n\nSELECT a.* FROM (SELECT * FROM table ORDER BY name, created_at) AS a ORDER BY a.name\n\nSELECT t0.* FROM table t0 WHERE t0.created_at IS NOT NULL ORDER BY t0.name, t0.created_at, t0.status LIMIT 10 OFFSET 10"; 
$result = preg_replace($re, "", $str);

Demo

答案 1 :(得分:1)

ORDER BY.*?(?=\)|$)

试试这个。empty space。见。演示。

https://regex101.com/r/tJ2mW5/22

$re = "/ORDER BY.*?(?=\\)|$)/mi";
$str = "SELECT * FROM table ORDER BY name\nSELECT a.* FROM (SELECT * FROM table ORDER BY name, creation_date) AS a ORDER BY a.name";
$subst = "";

$result = preg_replace($re, $subst, $str);