Question

此代码有效，但有一个例外。我从日历中导入表演日期。当代码抓住下一个性能日期时，我想让它读取它是在下午6点之前还是之后开始。如果之前，我希望它说＆＃34;今天＆＃34;如果它之后，我希望它说＆＃34;今晚。＆＃34;我尝试过使用$ dateEvent（＆＃34; H＆＃34;），但它说我正在调用一个函数。如何将事件的日期转换为我可以使用的变量？

function calendar_dates() {  
    $servername = "localhost";  
    $username = "angelsdb";  
    $password = "R#start2013";  
    $dbname = "angelsice";  
    $fromToday = date("Y-m-d");

    /// Create connection  
    $conn = new mysqli($servername, $username, $password, $dbname);  
    // Check connection  
    if ($conn->connect_error) {  
            die("Connection failed: " . $conn->connect_error);  
    }  

    $sql = "SELECT event_start_date, recurrence_interval, event_name, post_content, event_start_time, event_slug, event_all_day FROM wp_em_events";  
    $result = $conn->query($sql);  

    if ($result->num_rows > 0) {  
        // output data of each row  
        while($row = $result->fetch_assoc()) {  
            $fromCalendar = $row["event_start_date"];  
            $dateEvent = new DateTime($fromCalendar);  
            $dateToday = new DateTime($fromToday);  
            if(strtotime($fromToday) <= strtotime($fromCalendar) && $row["recurrence_interval"] < 1){   
                if($dateToday == $dateEvent) {  

                /// THIS IS WHERE I WANT TO TEST IF IT IS BEFORE 6PM OR AFTER USING THE VARIABLE $GREETING

                $time = new DateTime($row["event_start_time"]);  
                echo "<h2>" . $greeting . " @ " . $time->format('h:i a') . "</h2>";  
                echo "<a href='../events/". $row['event_slug'] . "'><h1>" . $row["event_name"] . "</h1></a>";  
                echo "<h3>" . $row["post_content"] . "</h3>";  

                } else {  

                $date = $dateEvent;  

                $time = new DateTime($row["event_start_time"]);  
                echo "<h2>" . $date->format('l') . " @ " . $time->format('h:i a') . "</h2>";  
                echo "<a href='../events/". $row['event_slug'] . "'><h1>" . $row["event_name"] . "</h1></a>";  
                echo "<h3>" . $row["post_content"] . "</h3>";  

                }  
                return;  
                }  
            }  
    } else {  
           echo "0 results";  
    }  

    mysqli_close($conn);  
}

Answer 1

试试这个

$dateEvent = "2011-07-26 20:05:00";//for example
$dateEvent = strtotime($dateEvent);
$time= date('H', $dateEvent);
if((int)$time>18)
    echo 'Tonight';
else 
    echo 'Today';

ideone

Answer 2

在下午6点将日期与DateTime比较，请参阅ideone

<?php

// your code goes here

$t1 = new DateTime("4:30pm");
$t2 = new DateTime("8:30pm");


function todayTonight($t) {
    return (new DateTime("6:00pm") < $t) ? "Tonight" : "Today";
}

echo todayTonight($t1) . "\n";
echo todayTonight($t2) . "\n";

如何将事件的日期/时间转换为可以使用的变量？

2 个答案: