我可以通过一个视图显示我的coffeescript错误消息(/users/new.html.erb):
<h1> Sign up! </h1>
<%= form_for (@user) do |f| %>
<%= f.label :email %><p class="error email-error"></p>
<%= f.email_field :email %>
<%= f.submit "Sign Up", class: 'btn' %>
<% end %>
和一个coffeescript文件(/users.js.coffee):
ready = ->
$('form').submit ->
$('.error').text ''
email = $('#user_email').val()
if email == ''
$('.email-error').text 'Please enter your email.'
false
return
$(document).ready(ready)
$(document).on('page:load', ready)
但是当我尝试添加第二个视图(/sessions/new.html.erb)时,两个表单的错误消息都不会显示:
<h1> Log In </h1>
<%= form_for(:session, url: login_path) do |f| %>
<%= f.label :email %><p class="error email-error"></p>
<%= f.email_field :email, :id => "session_email" %>
<%= f.submit "Log In", class: 'btn' %>
<% end %>
和coffeescript文件(/sessions/js.coffee):
main = ->
$('form').submit ->
$('.error').text ''
email = $('#session_email').val()
if email == ''
$('.email-error').text 'Please enter your email'
false
return
$(document).ready(main)
$(document).on('page:load', main)
我知道最终coffeescript会被rails编译成一个文件,所以它不会知道我引用的是哪种'形式'。但是当我尝试在表单中添加id标签时,我甚至无法获得一个表单。我已经被困2天了,无法解决这个问题。任何帮助将不胜感激。谢谢!
答案 0 :(得分:0)
在“mu太短”的帮助下,我能够在两个表单上显示错误消息。问题是.submit()绑定到一个表单并阻止它绑定到第二个表单。添加.unbind()修复了这个问题:
ready = ->
$('form.new_user').submit ->
$('.error').text ''
email = $('#user_email').val()
if email == ''
$('.email-error').text 'Please enter your email.'
$('form').unbind('submit')
false
return
$(document).ready(ready)
$(document).on('page:load', ready)
和第二个coffeescript文件:
main = ->
$('form.s_login').submit ->
$('.error').text ''
s_email = $('#session_email').val()
if s_email == ''
$('.email-error').text 'Please enter your email'
$('form').unbind('submit')
false
return
$(document).ready(main)
$(document).on('page:load', main)