Question

以下代码运行完美，但如果您点击＆＃34; x＆＃34;或者＆＃34;取消＆＃34;在对话框NullPointerException上抛出。我想回忆一下方法TestMessage并回到同一个对话框。

import javax.swing.JOptionPane;

public class Alpha {

  public void TestMessage() {

    Object [] tM1={"Option 1","Option 2","Option 3"};

    String mA2 = (String) JOptionPane.showInputDialog(null,"This is a test Message",null, JOptionPane.QUESTION_MESSAGE, null,tM1,tM1[0]);

    if (mA2.equals("Option 1")) {JOptionPane.showMessageDialog(null,"You chose Option 1");}
    if (mA2.equals("Option 2")) {JOptionPane.showMessageDialog(null,"You chose Option 2");}
    if (mA2.equals("Option 3")) {JOptionPane.showMessageDialog(null,"You chose Option 3");}

    }

    public static void main (String [] args) {

    Alpha A1=new Alpha();
    A1.TestMessage();

    }

    }

错误讯息：

java.lang.NullPointerException
at Alpha.TestMessage(Alpha.java:11)
at Alpha.main(Alpha.java:20)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at edu.rice.cs.drjava.model.compiler.JavacCompiler.runCommand(JavacCompiler.java:272)

Answer 1

如果按“取消”键，

showInputDialog会返回null。或者＆＃39; X＆＃39;所以你的检查if (mA2.equals("Option 1")访问null指针。只需先检查mA2 != null。

Java JOptionPane对话框NullPointerException

1 个答案: