Question

我试图这样做，但在某些位置，对象，在这种情况下，我的ImageView，只会传送＆＃34;在另一个程度上。

如何让它不会在JavaFX场景中不稳定并正确地跟随我的鼠标光标？

Answer 1

我最近在一篇关于how to create a heat seeking missile的博客文章中这样做了。

您的相关部分是此代码片段：

public void move() {  

 SpriteBase follower = this;  

 if( target != null)  
 {  
  //get distance between follower and target  
  double distanceX = target.getCenterX() - follower.getCenterX();  
  double distanceY = target.getCenterY() - follower.getCenterY();  

  //get total distance as one number  
  double distanceTotal = Math.sqrt(distanceX * distanceX + distanceY * distanceY);  

  //calculate how much to move  
  double moveDistanceX = this.turnRate * distanceX / distanceTotal;  
  double moveDistanceY = this.turnRate * distanceY / distanceTotal;  

  //increase current speed  
  follower.dx += moveDistanceX;  
  follower.dy += moveDistanceY;  

  //get total move distance  
  double totalmove = Math.sqrt(follower.dx * follower.dx + follower.dy * follower.dy);  

  //apply easing  
  follower.dx = missileSpeed * follower.dx/totalmove;  
  follower.dy = missileSpeed * follower.dy/totalmove;  

 }   

 //move follower  
 follower.x += follower.dx;  
 follower.y += follower.dy;  

 //rotate follower toward target  
 double angle = Math.atan2(follower.dy, follower.dx);  
 double degrees = Math.toDegrees(angle) + 90;  

 follower.r = degrees;  

}

跟随者是你的对象，目标是鼠标光标。您可以使用Point2D的Java 8功能来计算距离，这将使代码更少。出于与Java 7的兼容性原因，我没有这样做。

如果这有助于您，请告诉我。如果它不是您想要的，请更准确。

获取Image / Transform / Shape以旋转到JavaFX中的Follow Mouse Cursor

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