导入csv 导入运算符
writenames = "col1, Name, col2, col3, col4".split(",")
reader = csv.DictReader(open("Test.csv", "rb"))
writer = csv.DictWriter(open("Test1.csv", "wb"), \
fieldnames=writenames)
reorderfunct = lambda r: dict([(col, r[col]) for col in writenames])
writer.writeheader()
for row in reader:
writer.writerow(reorderfunct(row)
输出:
Traceback (most recent call last):
File "C:\Users\evan.keeler\My Documents\LiClipse Workspace\Test
Test\ColumnSwitch.py", line 10, in <module>
writer.writeheader()
File "C:\Python34\lib\csv.py", line 142, in writeheader
self.writerow(header)
File "C:\Python34\lib\csv.py", line 153, in writerow
return self.writer.writerow(self._dict_to_list(rowdict))
TypeError: 'str' does not support the buffer interface
我不确定这里的问题是什么?我知道你必须将字符串转换为字节,但我不知道如何使用这个特定的例子。
答案 0 :(得分:1)
在python3中,csv文件需要以文本模式打开,而不是二进制文件,需要使用newline =''打开它们。
reader = csv.DictReader(open("Test.csv", "r", newline=''))
writer = csv.DictWriter(open("Test1.csv", "w", newline=''), fieldnames=writenames)
这是csv.reader and csv.writer docs:
中唯一提到的如果csvfile是文件对象,则应使用newline =''
打开它
虽然DictReader和DictWriter也需要它。
只在python2中打开以二进制模式打开csv文件。
答案 1 :(得分:0)
您应该以文本模式打开文件,而不是二进制模式。
reader = csv.DictReader(open("Test.csv", "r"))
writer = csv.DictWriter(open("Test1.csv", "w"), fieldnames=writenames)