所以我一直在研究一个程序,它会显示搜索到的文本字符串的行号和行本身。如果我搜索狗,并且我的文本文件中包含单词dog的行,则应显示这些行和行号。我还创建了一个计算文本文件的字符,单词和行的方法。但是,我遇到的问题是,每当我运行程序时,我都不会使用搜索文本的行来获取行号。我成功地从控制台中的文本文件中获取了文本,并且我成功地获得了行数,单词等。
这是我的书面代码,我猜它必须做一些事实,即我没有"返回结果;"声明,但我不知道在哪里放,如果我把它添加到" +字符+"字符。 ""通过做" +结果",它只是给我空括号。
也许我做错了什么?也许与关闭文件和流有关,不确定。请帮助,我尝试过移动的东西,但没有运气。
public String words() {
try {
int words = 0;
int numbers = 0;
int lines = 1;
int characters = 0;
int total = 0;
String c = " ";
FileReader r = new FileReader(file1);
LineNumberReader lnr = new LineNumberReader(r);
StreamTokenizer t = new StreamTokenizer(r);
ArrayList<String> results = new ArrayList<String>();
t.resetSyntax();
t.wordChars('0', '9');
t.wordChars('A', 'Z');
t.wordChars('a', 'z');
t.whitespaceChars(0, ' ');
t.eolIsSignificant(true);
while (t.nextToken() != StreamTokenizer.TT_EOF) {
switch (t.ttype) {
case StreamTokenizer.TT_NUMBER:
numbers++;
break;
case StreamTokenizer.TT_WORD:
characters += t.sval.length();
words++;
break;
case StreamTokenizer.TT_EOL:
lines++;
break;
case StreamTokenizer.TT_EOF:
break;
default:
}
}
FileInputStream fstream = new FileInputStream(file1);
BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
String strLine;
while ((strLine = br.readLine()) != null) {
System.out.println(strLine);
}
br.close();
String ask = "Enter Word";
String find = JOptionPane.showInputDialog(ask);
String word = find;
String line = null;
while ((line = lnr.readLine()) != null) {
if (line.indexOf(word) >= 0) {
results.add(lnr.getLineNumber() + line);
}
}
r.close();
total = numbers + words;
lnr.close();
return file1.getName() + " has " + lines + " lines, "
+ total + " words, "
+ characters + " characters. ";
} catch (IOException e) {
display(e.toString(), "Error");
}
return " ";
}
如果需要,这里是主要课程:
import java.io.*;
import java.util.ArrayList;
import javax.swing.*;
public class BasicFile {
File file1;
JFileChooser selection;
File file2 = new File(".", "Backup File");
public BasicFile() {
selection = new JFileChooser(".");
}
public void selectFile() {
int status = selection.showOpenDialog(null);
try {
if (status != JFileChooser.APPROVE_OPTION) {
throw new IOException();
}
file1 = selection.getSelectedFile();
if (!file1.exists()) {
throw new FileNotFoundException();
}
} catch (FileNotFoundException e) {
JOptionPane.showMessageDialog(null, "File Not Found ", "Error", JOptionPane.INFORMATION_MESSAGE);
} catch (IOException e) {
System.exit(0);
}
}
public void backupFile() throws FileNotFoundException {
DataInputStream in = null;
DataOutputStream out = null;
try {
in = new DataInputStream(new FileInputStream(file1));
out = new DataOutputStream(new FileOutputStream(file2));
try {
while (true) {
byte data = in.readByte();
out.writeByte(data);
}
} catch (EOFException e) {
JOptionPane.showMessageDialog(null, "File has been backed up!",
"Backup Complete!", JOptionPane.INFORMATION_MESSAGE);
} catch (IOException e) {
JOptionPane.showMessageDialog(null, "File Not Found ",
"Error", JOptionPane.INFORMATION_MESSAGE);
}
} finally {
try {
in.close();
out.close();
} catch (Exception e) {
display(e.toString(), "Error");
}
}
}
boolean exists() {
return file1.exists();
}
public String toString() {
return file1.getName() + "\n" + file1.getAbsolutePath() + "\n" + file1.length() + " bytes";
}
public String words() {
try {
int words = 0;
int numbers = 0;
int lines = 1;
int characters = 0;
int total = 0;
String c = " ";
FileReader r = new FileReader(file1);
LineNumberReader lnr = new LineNumberReader(r);
StreamTokenizer t = new StreamTokenizer(r);
ArrayList<String> results = new ArrayList<String>();
t.resetSyntax();
t.wordChars('0', '9');
t.wordChars('A', 'Z');
t.wordChars('a', 'z');
t.whitespaceChars(0, ' ');
t.eolIsSignificant(true);
while (t.nextToken() != StreamTokenizer.TT_EOF) {
switch (t.ttype) {
case StreamTokenizer.TT_NUMBER:
numbers++;
break;
case StreamTokenizer.TT_WORD:
characters += t.sval.length();
words++;
break;
case StreamTokenizer.TT_EOL:
lines++;
break;
case StreamTokenizer.TT_EOF:
break;
default:
}
}
FileInputStream fstream = new FileInputStream(file1);
BufferedReader br = new BufferedReader(new InputStreamReader(fstream));
String strLine;
while ((strLine = br.readLine()) != null) {
System.out.println(strLine);
}
br.close();
String ask = "Enter Word";
String find = JOptionPane.showInputDialog(ask);
String word = find;
String line = null;
while ((line = lnr.readLine()) != null) {
if (line.indexOf(word) >= 0) {
results.add(lnr.getLineNumber() + line);
}
}
r.close();
total = numbers + words;
lnr.close();
return file1.getName() + " has " + lines + " lines, "
+ total + " words, "
+ characters + " characters. ";
} catch (IOException e) {
display(e.toString(), "Error");
}
return " ";
}
void display(String msg, String s) {
JOptionPane.showMessageDialog(null, msg, s, JOptionPane.ERROR_MESSAGE);
}
}
答案 0 :(得分:0)
你可以做的是开始计算文件中的行(starting by 0
),然后每次找到新行时increase by 1
..然后检查您要查找的字符串是否包含在行中,然后print the number of the line where the keyword is found
(使用Java中的contains()
函数)。我假设您要检查大写和小写,如果您不想要,那么只需删除toLowerCase()
!因此,在Java中正确读取文件:
long lineNumber = 0;
BufferedReader myReader = new BufferedReader(new FileReader("test.txt"));
String line = myReader.readLine();
while(line != null){
lineNumber++;
System.out.println("The line I am now examining is : " + line + " and the line number is : " + lineNumber);
if line.toLowerCase().contains(word.toLowerCase()) {
System.out.println("Line number: " + lineNumber + " contains keyword : " + word);
line = myReader.readLine();
}
答案 1 :(得分:0)
你快到了。
在while ((line = lnr.readLine()) != null)
循环之前重新初始化FileReader和LineNumberReader。
然后你的ArrayList将充满我认为你想要的#String。