我已经浏览了许多帖子，试图解释如何实现这一点，但没有人帮我解决问题。
我有一个HTML文件，其中包含一个XML解析JavaScript函数，该函数反过来呈现XSLT文件。问题是，我有多个记录＆＃39;在我的XML文件中，我只需要一个XSLT来呈现每个记录（而不是每个记录单独的XSLT文件）。根据下面的代码，有人可以建议我如何从包含记录ID的JavaScript（在我的XML文件中的每个XML记录中）传递一个参数，以便单个＆＃39; XSLT可以使用源自参数的正确数据解析布局。
HTML
<!DOCTYPE html>
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1.0, user-scalable=no" />
<title>Weather App</title>
<link href="../../css/materialize.css" type="text/css" rel="stylesheet" media="screen,projection" />
<link href="../../css/animate.css" type="text/css" rel="stylesheet" />
<link href="../../css/style.css" type="text/css" rel="stylesheet" media="screen,projection" />
</head>
<body>
<div id="WeatherDetailsContainer"></div>
<!-- Scripts-->
<script src="https://code.jquery.com/jquery-2.1.1.min.js"></script>
<script src="../../js/materialize.js"></script>
<script>
$(function(){
RenderXSLT();
});
function loadXMLDoc(filename) {
if (window.ActiveXObject) {
xhttp = new ActiveXObject("Msxml2.XMLHTTP");
} else {
xhttp = new XMLHttpRequest();
}
xhttp.open("GET", filename, false);
try {
xhttp.responseType = "msxml-document"
} catch (err) {} // Helping IE11
xhttp.send("");
return xhttp.responseXML;
}
function RenderXSLT() {
xml = loadXMLDoc("datastore/Weather.xml");
xslt = loadXMLDoc("transformations/WeatherDetailsCard.xslt");
var currentLocation = localStorage.getItem('current_weather_location');
if (window.ActiveXObject || xhttp.responseType == "msxml-document") {
ex = xml.transformNode(xslt);
document.getElementById("WeatherDetailsContainer").innerHTML = ex;
}
else if (document.implementation && document.implementation.createDocument) {
xsltProcessor = new XSLTProcessor();
xsltProcessor.importStylesheet(xslt);
/** I believe this is how to set the param, but it didn't work **/
//xsltProcessor.setParameter(null, "cityname", currentLocation);
resultDocument = xsltProcessor.transformToFragment(xml, document);
document.getElementById("WeatherDetailsContainer").appendChild(resultDocument);
}
}
</script>
</body>
</html>
XML文件
<?xml version="1.0" encoding="UTF-8" ?>
<locations>
<location>
<cityid>Lon</cityid>
<cityname>London</cityname>
<temperature>11</temperature>
<high>13</high>
<low>4</low>
<date>17/03/2015</date>
</location>
<location>
<cityid>Man</cityid>
<cityname>Manchester</cityname>
<temperature>07</temperature>
<high>08</high>
<low>2</low>
<date>17/03/2015</date>
</location>
<location>
<cityid>Gla</cityid>
<cityname>Glasgow</cityname>
<temperature>05</temperature>
<high>06</high>
<low>1</low>
<date>17/03/2015</date>
</location>
</locations>
XSLT文件
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<!-- How do I use the value of the parameter sent via JavaScript for the cityname (in place of value 'London') -->
<xsl:for-each select="locations/location[cityname='London']">
<div class="section">
<div class="container">
<div class="row">
<div class="col s4 m4 l4">
<div class="card-panel z-depth-3 animated fadeInUp" style="padding:10px 10px 5px 10px !important;">
<span class="center-align">
<h5><xsl:value-of select="cityname"/></h5><span> (<xsl:value-of select="cityid"/>)</span>
</span>
<p>Temp: <xsl:value-of select="temperature"/></p>
<p>High: <xsl:value-of select="high"/></p>
<p>Low: <xsl:value-of select="low"/></p>
</div>
</div>
</div>
</div>
</div>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
答案 0 :(得分：5)
在XSLT中，您需要更改
<xsl:template match="/">
<!-- How do I use the value of the parameter sent via JavaScript for the cityname (in place of value 'London') -->
<xsl:for-each select="locations/location[cityname='London']">
到
<xsl:param name="cityname"/>
<xsl:template match="/">
<!-- How do I use the value of the parameter sent via JavaScript for the cityname (in place of value 'London') -->
<xsl:for-each select="locations/location[cityname = $cityname]">
我也会设置<xsl:output method="html"/>，因为你只创建一个HTML片段，如果你没有设置输出方法，XSLT处理器不知道。
在Mozilla，Chrome，Opera的Javascript代码中，我会更改支票
else if (document.implementation && document.implementation.createDocument) {
xsltProcessor = new XSLTProcessor();
xsltProcessor.importStylesheet(xslt);
/** I believe this is how to set the param, but it didn't work **/
//xsltProcessor.setParameter(null, "cityname", currentLocation);
resultDocument = xsltProcessor.transformToFragment(xml, document);
document.getElementById("WeatherDetailsContainer").appendChild(resultDocument);
}
到
else if (typeof XSLTProcessor !== 'undefined') {
var xsltProcessor = new XSLTProcessor();
xsltProcessor.importStylesheet(xslt);
xsltProcessor.setParameter(null, "cityname", currentLocation);
var resultFragment = xsltProcessor.transformToFragment(xml, document);
document.getElementById("WeatherDetailsContainer").appendChild(resultFragment);
}
使用transformNode的IE代码不允许设置参数，您还需要更改该部分，更改
if (window.ActiveXObject || xhttp.responseType == "msxml-document") {
ex = xml.transformNode(xslt);
document.getElementById("WeatherDetailsContainer").innerHTML = ex;
}
到
if (window.ActiveXObject || xhttp.responseType == "msxml-document") {
var template = new ActiveXObject('Msxml2.XslTemplate');
template.stylesheet = xslt;
var proc = template.createProcessor();
proc.input = xml;
proc.addParameter('cityname', currentLocation);
proc.transform();
document.getElementById("WeatherDetailsContainer").innerHTML = proc.output;
}
答案 1 :(得分：1)
看起来您在Javascript中使用了正确的代码来传递参数，但是您的XSLT也必须编写为接受参数：
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<!-- Declare it here -->
<xsl:param name="cityName" />
<xsl:template match="/">
<!-- use it here ------v -->
<xsl:for-each select="locations/location[cityname = $cityName]">
...
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>