Question

我不是＆＃34;亲＆＃34;在SQL中。

我有以下情况：

表：favcolor

 User   |Red    |Blue   |Yellow |Green  |Black
 Klaus  |0      |1      |1      |0      |0
 Jessy  |1      |0      |1      |0      |1 
 Andy   |1      |1      |0      |0      |0 
 Alex   |0      |0      |0      |1      |1 
 Denis  |1      |1      |0      |0      |1

HTML代码

 <form method="post" action="./usercolor.php"> <input type="checkbox" id="colorred" name="colorred" value="1" />red</td>
 <input type="checkbox" id="colorblue" name="colorblue" value="1" />blue</td>
 <input type="checkbox" id="coloryellow" name="coloryellow" value="1" />yellow</td>
 <input type="checkbox" id="colorgreen" name="colorgreen" value="1" />green</td>
 <input type="checkbox" id="colorblack" name="colorblack" value="1" />black</td>
 <input type="submit" value="SEARCH" /> </form>

PHP / SQL（使用MySQL 5.6）：

    $colorred       =   $_POST["colorred"];
    $colorblue      =   $_POST["colorblue"];
    $colorgreen     =   $_POST["colorgreen"];
    $coloryellow    =   $_POST["coloryellow"];
    $colorblack     =   $_POST["colorblack"];

SELECT * FROM favcolor WHERE red = '".$colorred."' AND blue = '".$colorblue."' AND green = '".$colorgreen."' AND yellow = '".$coloryellow."' AND black = '".$colorblack."'

现在我的问题：例如，我想知道哪个用户喜欢黄色。然后我检查id＆＃34; coloryellow＆＃34;上的复选框。并按＆＃34; SEARCH＆＃34;。但我没有收到任何结果，因为＆＃34; AND＆＃34; SQL语句中的运算符是错误的...... 哪个操作员必须使用我的SQL语句给我两个结果？

Answer 1

$whereArr = Array();
if (isset($_POST["colorred"]) && $_POST["colorred"]==1) $whereArr[] = "red=1";
if (isset($_POST["colorblue"]) && $_POST["colorblue"]==1) $whereArr[] = "blue=1";
if (isset($_POST["colorgreen"]) && $_POST["colorgreen"]==1) $whereArr[] = "green=1";
if (isset($_POST["coloryellow"]) && $_POST["coloryellow"]==1) $whereArr[] = "yellow=1";
if (isset($_POST["colorblack"]) && $_POST["colorblack"]==1) $whereArr[] = "black=1";

$sqlStr = "SELECT * FROM favcolor WHERE " . implode(" AND ", $whereArr);

然后运行查询

来自数据库的SQL语句

1 个答案: