简化要在r中分组的代码

时间:2015-03-17 15:47:52

标签: r simplify

我有一个这样的数据框:

ID PA   WA  PC
1   2   -6   8 
2   2   -2   7
3   3    7   2
4  -3    3  -6
5   3   20  12
6  15  -17  18
7   3    6  10

我尝试根据他们在PA,WA和PC上的得分对ID进行分组。

我已经使用过这个,但它太麻烦了:

NEW1 <- subset(WA.PC.PA, PA< -5 & WA < -5 & PC> 5, select=c(id, PA, WA, PC))
NEW2 <- subset(WA.PC.PA, PA >5 & WA < -5 & PC< -5, select=c(id, PA, WA, PC))
NEW3 <- subset(WA.PC.PA, PA < -5 & WA >5 & PC< -5, select=c(id, PA, WA, PC))
NEW4 <- subset(WA.PC.PA, PA < -5 & WA < -5 & PC< -5, select=c(id, PA, WA, PC))
NEW5 <- subset(WA.PC.PA, PA > 5 & WA >5 & PC< -5, select=c(id, PA, WA, PC))
NEW6 <- subset(WA.PC.PA, PA >5 & WA < -5 & PC>5, select=c(id, PA, WA, PC))
NEW7 <- subset(WA.PC.PA, PA < -5 & WA >5 & PC>5, select=c(id, PA, WA, PC))
NEW8 <- subset(WA.PC.PA, PA >5 & WA >5 & PC>5, select=c(id, PA, WA, PC))
NEW9 <- subset(WA.PC.PA, PA<5 & PA>-5 & WA<5 & WA>-5 & PC<5 & PC>-5, select=c(id, PA, WA, PC))
NEW10 <- subset(WA.PC.PA, PA < -5 & WA < -5 & PC<5 & PC>-5, select=c(id, PA, WA, PC))
NEW11 <- subset(WA.PC.PA, PA<5 & PA>-5 & WA < -5 & PC<5 & PC>-5, select=c(id, PA, WA, PC))
NEW12 <- subset(WA.PC.PA, PA<5 & PA>-5 & WA<5 & WA>-5 & PC< -5, select=c(id, PA, WA, PC))
NEW13 <- subset(WA.PC.PA, PA< -5 & WA<5 & WA>-5 & PC<5 & PC>-5, select=c(id, PA, WA, PC))
NEW14 <- subset(WA.PC.PA, PA < -5 & WA<5 & WA>-5 & PC< -5, select=c(id, PA, WA, PC))
NEW15 <- subset(WA.PC.PA, PA< -5 & WA<5 & WA>-5 & PC>5, select=c(id, PA, WA, PC))
NEW16 <- subset(WA.PC.PA, PA < -5 & WA >5 & PC<5 & PC>-5, select=c(id, PA, WA, PC))
NEW17 <- subset(WA.PC.PA, PA<5 & PA>-5 & WA < -5 & PC>5, select=c(id, PA, WA, PC))
NEW18 <- subset(WA.PC.PA, PA<5 & PA>-5 & WA<5 & WA>-5 & PC< -5, select=c(id, PA, WA, PC))
NEW19 <- subset(WA.PC.PA, PA<5 & PA>-5 & WA<5 & WA>-5 & PC>5, select=c(id, PA, WA, PC))
NEW20 <- subset(WA.PC.PA, PA<5 & PA>-5 & WA >5 & PC< -5, select=c(id, PA, WA, PC))
NEW21 <- subset(WA.PC.PA, PA<5 & PA>-5 & WA >5 & PC<5 & PC>-5, select=c(id, PA, WA, PC))
NEW22 <- subset(WA.PC.PA, PA<5 & PA>-5 & WA >5 & PC>5, select=c(id, PA, WA, PC))
NEW23 <- subset(WA.PC.PA, PA >5 & WA < -5 & PC<5 & PC>-5, select=c(id, PA, WA, PC))
NEW24 <- subset(WA.PC.PA, PA >5 & WA<5 & WA>-5 & PC< -5, select=c(id, PA, WA, PC))
NEW25 <- subset(WA.PC.PA, PA >5 & WA<5 & WA>-5 & PC<5 & PC>-5, select=c(id, PA, WA, PC))
NEW26 <- subset(WA.PC.PA, PA >5 & WA<5 & WA>-5 & PC>5, select=c(id, PA, WA, PC))
NEW27 <- subset(WA.PC.PA, PA >5 & WA >5 & PC<5 & PC>-5, select=c(id, PA, WA, PC))

如您所见,我将每个分数分为三个等级,&lt; -5,介于-5~5和&gt; 5之间。但我想1)简化代码,因为当我想为每个测试的分数分配不同的数字时,我需要重写整个代码。

我该怎么做?

1 个答案:

答案 0 :(得分:1)

执行此操作的最佳方法是使用剪切然后进行交互然后拆分。基本上,cut将定义每个变量的分区,例如

paCuts = with(WA.PC.PA, cut(PA, c(-Inf, -5, 5, Inf)))
waCuts = with(WA.PC.PA, cut(PA, c(-Inf, -5, 5, Inf)))
levels = interaction(paCuts, waCuts)
split(WA.PC.PA, levels)

这样做的好处是,您可以将分区视为数据,即在向量中,而不是代码;在条件陈述中。它使各种切割变得轻而易举。