我创建了此脚本以从各种Web源读取。此脚本更新所有通知(邮件,帖子,朋友)和他们自己的下拉窗口的详细信息以及两个侧面更新栏。我在我的顶级manu.php页面中使用了这个脚本。
此脚本适用于登录用户。
现在我使用JavaScript var uid = '<? echo $session->id; ?>';
传递会话ID变量因此,当用户未登录时,我的浏览器控制台显示500 Internal Server Error
,因为此处会话没有ID,因此它传递了uid =''< / p>
我如何克服这个问题?
这是我的JavaScript脚本:
var uid = '<? echo $session->id; ?>';
function addmailno(type, msg){
//Do something for display mail/friend/post notification
}
function addmailup(type, msg){
//Do something for display mail/post/friend drop-down.
}
function addside(type, msg){
//Do something for display all friend/new post in side bar.
}
function waitFormailno(){
$.ajax({
type: "GET",
url: "serverforupandside.php",
cache: false,
async : false,
dataType : 'json',
data: "uid="+ uid,
timeout:15000,
success: function(data){
addmailno("MyDivClass", data);
addmailup("MyDivClass", data);
addside("MyDivId", data);
setTimeout(waitFormailno, 15000);
},
error: function(){
setTimeout(waitFormailno, 15000);
}
});
}
$(document).ready(function(){
waitFormailno();
});
serverforupandside.php
<?php
include("db.php");
include_once("mysession.php");
while (true) {
if($_GET['uid']){
global $dbh;
//All php query is here one after one
//Output is here by data
$data = array();
$data['upmail'] = $upmail;
$data['upfollow'] = $upfollow;
$data['uppost'] = $uppost;
// etc all
if (!empty($data)) {
echo json_encode($data);
flush();
mysqli_close($dbh);
}
}
mysqli_close($dbh);
}
?>
答案 0 :(得分:0)
您的 Javascript代码应修改为:
function waitFormailno(){
$.ajax({
type: "GET",
url: "serverforupandside.php",
cache: false,
async : false,
dataType : 'json',
data: "uid="+ uid,
timeout:15000,
success: function(data){
addmailno("MyDivClass", data);
addmailup("MyDivClass", data);
addside("MyDivId", data);
}
});
}
$(document).ready(function(){
setInterval(waitFormailno, 15000); // calls a function or evaluates an expression at specified intervals (in milliseconds)
});
PHP代码:
<?php
include("db.php");
include_once("mysession.php");
if (!empty($_GET['uid'])) {
global $dbh;
//All php query is here one after one
//Output is here by data
$data = array();
$data['upmail'] = $upmail;
$data['upfollow'] = $upfollow;
$data['uppost'] = $uppost;
// etc all
if (!empty($data)) {
echo json_encode($data);
}
}
此外,您应该在填充$data
数组之前添加验证。