Question

SELECT `Id`,`Amount`,'CreationTime' 
FROM `Table1` 
WHERE Amount IS NOT NULL GROUP BY `Id`;

以下查询给我结果：

有两列，数据按组排序。

   ID       |   Cash    |  CreationTime
   1        |   12      |   2015-10-30 07:59:11.000000
   1        |   10      |   2014-10-07 08:55:27.000000
   1        |   3       |   2012-10-05 06:35:48.000000
   2        |   100     |   2015-10-30 07:59:11.000000
   2        |   10      |   2014-10-07 08:55:27.000000
   3        |   3       |   2012-10-05 06:35:48.000000

现在我想从这个结果中获取一行，具体取决于该行的创建时间。我需要行数量= 3，因为它的创建时间最长。

我想要的输出：

     ID       |   Cash    |  CreationTime
      1       |   3       |   2012-10-05 06:35:48.000000
      2       |   10      |   2014-10-07 08:55:27.000000
      3       |   3       |   2012-10-05 06:35:48.000000

我的表中有专栏“Createtime”。所以，任何人都可以帮助我，我该怎么做？

我通过使用获得的结果：

SELECT Id,Amount,Creationtime
FROM Table1
WHERE Amount IS NOT NULL GROUP BY Id order by Creationtime
LIMIT 1;

或者使用这个：

SELECT `Id`,`Amount`,'CreationTime'  
 FROM `Table1` 
 WHERE Amount IS NOT NULL  order by CreationTime asc limit 0,1

RESULT

  ID       |   Cash    |  CreationTime
  1        |   3       |   2012-10-05 06:35:48.000000

Answer 1

您的解决方案：

SELECT `Id`,`Amount` 
FROM `Table1` 
WHERE Amount IS NOT NULL GROUP BY `Id` order by Createtime desc Limit 1

Answer 2

您的查询应该是：

SELECT `Id`,`Amount`,'CreationTime' 
FROM `Table1` 
where DATE_FORMAT('CreationTime', '%h-%i') = '06-35'
WHERE Amount IS NOT NULL GROUP BY `Id`;

如果您想要24小时格式的格式，也可以使用％H。

Answer 3

 SELECT `Id`,`Amount`,'CreationTime'  
 FROM `Table1` 
 WHERE Amount IS NOT NULL group by Id order by CreationTime asc limit 0,1

如何使用sql获得所需的结果

3 个答案: