有没有办法在元素中选择仅使用HTML + CSS显示的行和/或列?
样品:
HTML:
<div id="long">
<div>1</div>
<div>2</div>
<div>3</div>
<div>4</div>
<div>5</div>
<div>6</div>
<div>7</div>
<div>8</div>
<div>9</div>
</div>
<div id="short">
<div>1</div>
<div>2</div>
<div>3</div>
<div>4</div>
<div>5</div>
<div>6</div>
<div>7</div>
<div>8</div>
<div>9</div>
</div>
CSS:
div { font-family: courier; }
div div { display: inline-block; }
#long, #short { margin: 1em; }
#long { width: 4em; border: 1px solid red; }
#short { width: 2em; border: 1px solid blue; }
的jsfiddle:
说这个显示如下:
我想将样式应用于显示的列。例如。如果我想在红色矩形中设置第二列的样式,我想选择元素2,5和8.对于第二行蓝色矩形,我想选择元素3和4。
我不知道行/列中元素的数量,这取决于矩形的宽度,这不是常数。
答案 0 :(得分:0)
您可以查看nth_child selection in css 对于你想要实现的目标
<div id="long">
<div>1</div>
<div>2</div>
<div>3</div>
<div>4</div>
<div>5</div>
<div>6</div>
<div>7</div>
<div>8</div>
<div>9</div>
</div>
<div id="short">
<div>1</div>
<div>2</div>
<div>3</div>
<div>4</div>
<div>5</div>
<div>6</div>
<div>7</div>
<div>8</div>
<div>9</div>
</div>
现在来自#long
#long div:nth-child(2),#long div:nth-child(5),#long div:nth-child(8)
{
border: 1px solid black;
}
来自#short
#short div:nth-child(3),#short div:nth-child(4)
{
border: 1px solid black;
}
希望它有所帮助!