Question

如何基于此查询创建排名PHP函数：

SELECT @rownum := @rownum + 1 AS rank
    , id, name, avatar, views
    FROM users
    , (SELECT @rownum := 0) AS dummy
    WHERE users.group_id = 5
    ORDER BY views DESC

类似的东西：

function $rank {
    $rank = SELECT @rownum := @rownum + 1 AS rank, id, name, avatar, views FROM users, (SELECT @rownum := 0) AS dummy WHERE users.group_id = 5 ORDER BY views DESC;
    return $rank;
}

然后回应我网站上的排名。我的想法是在我需要使用它的每个地方（用户列表或用户个人资料）获得用户排名

Answer 1

编辑：这应该可以解决问题。

<?php
function getUserRank($group) {
$query = "SELECT id, name, avatar, views "
       . "FROM users "
       . "WHERE users.group_id = :group "
       . "ORDER BY views DESC";

// Execute query. This is the PDO version
$query = $db->prepare($query);
$query->bindValue(':group', $group);
$query->execute();

return $query->fetchAll(PDO::FETCH_ASSOC);    
} 

// Call function and pass the group ID over;
$list = getUserRank($group);

for ($i = 1; $i <= (count($list)); $i++) {
echo "$i -> $list->[name] -> $list->[$avatar] -> $list->[views]";
}
?>

php函数基于sql查询

1 个答案: