scala match *从xsd生成的字符串* maxOccurs =＆＃34; unbounded＆＃34;

Question

我有一个xsd：

  <xs:complexType name="records">
    <xs:sequence>
      <xs:element maxOccurs="unbounded" minOccurs="0" name="return" type="xs:string"/>
    </xs:sequence>
  </xs:complexType>

scalaxb生成了这段代码：

case class Records(returnValue: String*)

我尝试了这种模式匹配：

... match {
  case Records(ids: String*) =>
    ...

然后编译错误是：

')' expected but identifier found.
        case Records(ids: String*) =>
                                ^

我也尝试了case Records(ids: Array[String])和case Records(ids: Seq[String])，但没有成功。

如何使用scala模式匹配来匹配此类？

Answer 1

scala> Records("a", "b") match {
         case Records(strings @ _*) => strings.foreach(println)
       }
a
b


scala> Records("a", "b") match {
         case Records(one) => println("one")
         case Records(one, two) => println("two")
         case Records(one, two, rest @ _*) => println("more than two")
       }
two