Question

我正在创建一个获取位置类型的应用程序

我收到此错误

Model item passed into the dictionary is of type 'System.Collections.Generic.List[CA1API.Models.Weather]', but this requires model item type 'System.Collections.Generic.IEnumerable [CA1API.Models.Location]'.

我创建了一个看起来像这样的ViewModel 命名空间CA1API.Models

{
    public enum County
    {
        Ireland,
        England,
        Iceland
    }

    public class Location
    {
        public int LocationID { get; set; }
        [Display(Name = "Location")]
        public County LocationName { get; set; }
        public double Lat { get; set; }
        public double Lon { get; set; }
        public int WeatherID { get; set; }
        public List<Weather> Weathers { get; set; }

    }
}

我的控制器看起来像这样

public class HomeController : Controller
    {
        private WeatherDb db = new WeatherDb();
        public ActionResult Index()
        {

            return View(db.Weathers.ToList());
        }
    }

我的观点看起来像这样

@model IEnumerable<CA1API.Models.Location>
<div class="row">
    <div class="col-md-2">
        <div class="panel panel-success">
            <div class="panel-heading">County</div>
            <div>
                <div class="panel-body" style="overflow-x:hidden; height:300px;">
                    @foreach (var item in Model)
                    {
                        <p>modelItem=>item.County</p>
                    }
                </div>
            </div>
        </div>
    </div>

Answer 1

您的Index 查看使用@model IEnumerable<CA1API.Models.Location>作为模型，并尝试将@model List<CA1API.Models.Weather>传递给图

因为您尝试传递的模型不是继承，或者它不是预期会被接收的模型，所以它会抛出异常。

传递到字典中的模型项是类型＆＃39; System.Collections.Generic.List [CA1API.Models.Weather]＆＃39;，但是这个需要模型项类型＆＃39; System.Collections.Generic.IEnumerable [CA1API.Models.Location]＆＃39;

Answer 2

错误很清楚。您传递的视图需要List<Weather> IEnumerable<Location>。{/ p>

您可能需要return View(db.Locations.ToList());而不是db.Weathers。

传递到字典中的模型项的类型是＆＃39; System.Collections.Generic.List [CA1API.Models.Weather]＆＃39;

2 个答案: