Question

我不明白为什么我运行这个小程序时屏幕上没有显示任何内容？ while循环是否开始了？

#include <stdio.h>
#include <string.h>

int main()
{
  char word[20]; 
  char TryAgain[20] = "y";
  int WordLength = 0;

  while (strcmp(TryAgain, "y"))
  {
    printf("\t\t\t Word \n\n");
    printf("What is your word, bird?\n");
    scanf("%s", word);
    getchar();

    WordLength = strlen(word); 

    printf("Result: "); 
    for (int i = 0; i < WordLength; ++i)
    {
        printf("%c*", word[i]);
    }
    printf("\nWould you like to try another word? [y/n]\n");
    scanf("%s", TryAgain);
  }

  getchar();
  return 0;
}

Answer 1

如果

strcmp的参数相同，则返回0，因此在第一次迭代时，while循环检查while(0)。 0在布尔检查中等效于false，因此跳过while循环。试试while(!strcmp(TryAgain, "y"))。

Answer 2

我更喜欢将其更改为do-while

do {
  printf("\nWould you like to try another word? [y/n]\n");
  scanf("%s", TryAgain);
} while (TryAgain=="y" || TryAgain=="Y");

TryAgain必须是布尔值。见你

遇到while循环问题

2 个答案: