Question

client = input("What is your Client ID. CaSe SeNsItIvE")
file = open("clientIntensity.txt" , "r")
found = False
for line in file:
    if (client) in line:
      found = True

我想制作程序，以便在输入正确的客户端ID时，它会在给定的.txt文件中搜索ID。找到后，它将打印6-14个字符（它们是“高”或“中等”）。然后它将根据6-14个字符打印一些内容。到目前为止，我做了那么多......谢谢！（Python 3.4.2）

Answer 1

如果您只想打印包含客户端ID的行的第6到第14个字符，可以执行以下操作：

client = input("What is your Client ID. CaSe SeNsItIvE")
file = open("clientIntensity.txt" , "r")
for line in file:
    if client in line:
        print(line[5:13])
        break

（你使用5和13来获得第6-14个字符，因为第一个字符编号为零）

编辑。如果你想根据第6-14个字符的内容打印一些东西，你可以这样做：

def get_security(filename, client_id):
    with open(filename, 'r') as f:
        for line in f:
            if client_id in line:
                return line[5:13]

client = input("What is your Client ID. CaSe SeNsItIvE")
security = get_security('clientIntensity.txt', client)
if security is None:
    print ("Client ID not found")
elif security.startswith('High'):
    print('Good')
elif security == 'Moderate':
    print('Bad')
else:
    print('There has been an error')

从.txt文件中读取并从中创建条件

1 个答案: