Question

我正在使用Twitter API，而且我有以下字符串让我烦恼Proyecto de ingeniera comercial, actual Profesora de matemáticas \u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000Enseña Chile
我想将它存储在PostgreSql中，但不接受\u0000，所以我想替换它。
我尝试使用string= string.replaceAll("\\u0000", "");，但它不起作用。我刚刚得到以下

String json = TwitterObjectFactory.getRawJSON(user);
System.out.println(json);
json = json.replaceAll("\\u0000", "");
System.out.println(json);

输出（只有重要部分）

Proyecto de ingeniera comercial, actual Profesora de matemáticas \u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000Enseña Chile
Proyecto de ingeniera comercial, actual Profesora de matemáticas \u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000\u0000Enseña Chile

如果我把那个部分放在java中的一个字符串中替换有效，但如果我把它放在一个文本文件中，或者我直接为Twitter读它就不行了。所以我的问题是，如何替换\一个字符串的u0000？
顺便说一下，完整的字符串就是这个

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Answer 1

string = string.replace("\u0000", ""); // removes NUL chars
string = string.replace("\\u0000", ""); // removes backslash+u0000

具有u-escaping的角色在java源代码级别完成。例如＆＃34; class＆＃34;是：

public \u0063lass C {

此外，您不需要正则表达式。

Answer 2

replaceAll的第一个参数是正则表达式，Java正则表达式引擎理解\uNNNN转义为

json.replaceAll("\\u0000", "")

将搜索正则表达式 \u0000，它匹配实际字符串的Unicode NUL字符（U + 0000）， not 实例的实例{ {1}}。如果要匹配字符串\u0000，则需要使用正则表达式\u0000，这反过来表示Java字符串文字\\u0000

"\\\\u0000"

或者更简单地说，使用json.replaceAll("\\\\u0000", "")（其第一个参数是文字字符串而不是正则表达式）而不是replace

replaceAll

Answer 3

在某些情况下，输入文本包含多个反斜杠，后跟 \u0000。处理所有情况

<块引用>

  String test = "ABC\\u0000DEF\\\\u0000123";
  System.out.println(test.replaceAll("[\\\\]+u0000",""));

Java - 从String中删除\ u0000

3 个答案: