Question

我想获得一个通过Twitter API收藏特定状态的用户列表。我可以看到每个状态都有它所获得的收藏数量，但我需要获得最喜欢的用户列表。

有关如何实现这一目标的任何想法？

Answer 1

这是在Python 2.7.x中实现的变通方法或黑客攻击：

import urllib2
import re

def get_user_ids_of_post_likes(post_id):
    try:
        json_data = urllib2.urlopen('https://twitter.com/i/activity/favorited_popup?id=' + str(post_id)).read()
        found_ids = re.findall(r'data-user-id=\\"+\d+', json_data)
        unique_ids = list(set([re.findall(r'\d+', match)[0] for match in found_ids]))
        return unique_ids
    except urllib2.HTTPError:
        return False

# Example: 
# https://twitter.com/golan/status/731770343052972032

print get_user_ids_of_post_likes(731770343052972032)

# ['13520332', '416273351', '284966399']
#
# 13520332 +> @TopLeftBrick
# 416273351 => @Berenger_r
# 284966399 => @FFrink

Answer 2

对于使用Python 3的用户，您需要解码HTML字符串，以避免出现TypeError。

import urllib
import re

def get_user_ids_of_post_likes(post_id):
    try:
        json_data = urllib.request.urlopen('https://twitter.com/i/activity/favorited_popup?id=' + str(post_id)).read()
        json_data = json_data.decode('utf-8')
        found_ids = re.findall(r'data-user-id=\\"+\d+', json_data)
        unique_ids = list(set([re.findall(r'\d+', match)[0] for match in found_ids]))
        return unique_ids

    except urllib.request.HTTPError:
        return False

# Example: 
# https://twitter.com/golan/status/731770343052972032

print get_user_ids_of_post_likes(731770343052972032)

# ['13520332', '416273351', '284966399']
#
# 13520332 +> @TopLeftBrick
# 416273351 => @Berenger_r
# 284966399 => @FFrink

Twitter API - 获取收藏状态的用户列表

2 个答案: