我一直在尝试重载运算符<<所以我可以用我的枚举类型做到这一点:
/* enum class Color { ... } */
Color color = GetColor();
std::wcout << L"The color is " << color << std::endl;
输出:
The color is Green.
以下是我在Visual Studio 2013中编译的一些测试代码:
#include <iostream>
#include <string>
/* (global scope) */
enum class enum_type_1 { e1_enumerand };
inline std::ostream& operator<<(std::ostream& os, enum_type_1 value)
{
return os << L"e1_enumerand"; // switch-cases omitted
}
class cls
{
public:
enum class enum_type_2 { e2_enumerand };
friend inline std::ostream& operator<<(std::ostream& os, enum_type_2 value)
{
return os << L"e2_enumerand"; // switch-cases omitted
}
};
namespace ns
{
enum class enum_type_3 { e3_enumerand };
inline std::ostream& operator<<(std::ostream& os, enum_type_3 value)
{
return os << L"e3_enumerand"; // switch-cases omitted
}
}
int _tmain(int argc, wchar_t* argv[])
{
enum_type_1 e1 = enum_type_1::e1_enumerand;
cls::enum_type_2 e2 = cls::enum_type_2::e2_enumerand;
ns::enum_type_3 e3 = ns::enum_type_3::e3_enumerand;
std::wcout << L"The value of e1 is " << e1 << std::endl;
std::wcout << L"The value of e2 is " << e2 << std::endl;
std::wcout << L"The value of e3 is " << e3 << std::endl;
std::cin.ignore();
return 0;
}
如果我用“class”替换定义中的“enum class”,这将编译,但输出是枚举的整数值,所以我的重载没有找到。
如果我留下“enum class”(我更喜欢类型安全的枚举),则完全无法编译,并出现以下错误:
d:\...\main.cpp(43): error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'enum_type_1' (or there is no acceptable conversion)
(帖子底部有更多错误详情)
我一直在谷歌搜索,阅读和尝试各种排列,我根本无法让这个工作。谁能发现我做错了什么?
以下是我收到的错误消息的详细信息。请注意,编译器通过ADL找到我的重载,但不认为它们匹配。签名看起来和我一样...... WTF?
d:\...\main.cpp(43): error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'enum_type_1' (or there is no acceptable conversion)
c:\...\ostream(498): could be 'std::basic_ostream<wchar_t,std::char_traits<wchar_t>> &std::basic_ostream<wchar_t,std::char_traits<wchar_t>>::operator <<(std::basic_streambuf<wchar_t,std::char_traits<wchar_t>> *)'
.
.
.
d:\...\main.cpp(11): or 'std::ostream &operator <<(std::ostream &,enum_type_1)'
.
.
.
with
[
_Ty=enum_type_1
]
while trying to match the argument list '(std::basic_ostream<wchar_t,std::char_traits<wchar_t>>, enum_type_1)'
d:\...\main.cpp(44): error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'cls::enum_type_2' (or there is no acceptable conversion)
c:\...\ostream(498): could be 'std::basic_ostream<wchar_t,std::char_traits<wchar_t>> &std::basic_ostream<wchar_t,std::char_traits<wchar_t>>::operator <<(std::basic_streambuf<wchar_t,std::char_traits<wchar_t>> *)'
.
.
.
d:\...\main.cpp(11): or 'std::ostream &operator <<(std::ostream &,enum_type_1)'
d:\...\main.cpp(21): or 'std::ostream &operator <<(std::ostream &,cls::enum_type_2)' [found using argument-dependent lookup]
.
.
.
c:\...\ostream(988): or 'std::basic_ostream<wchar_t,std::char_traits<wchar_t>> &std::operator <<<wchar_t,std::char_traits<wchar_t>,cls::enum_type_2>(std::basic_ostream<wchar_t,std::char_traits<wchar_t>> &&,const _Ty &)'
with
[
_Ty=cls::enum_type_2
]
while trying to match the argument list '(std::basic_ostream<wchar_t,std::char_traits<wchar_t>>, cls::enum_type_2)'
d:\...\main.cpp(45): error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'ns::enum_type_3' (or there is no acceptable conversion)
c:\...\ostream(498): could be 'std::basic_ostream<wchar_t,std::char_traits<wchar_t>> &std::basic_ostream<wchar_t,std::char_traits<wchar_t>>::operator <<(std::basic_streambuf<wchar_t,std::char_traits<wchar_t>> *)'
.
.
.
d:\...\main.cpp(11): or 'std::ostream &operator <<(std::ostream &,enum_type_1)'
d:\...\main.cpp(31): or 'std::ostream &ns::operator <<(std::ostream &,ns::enum_type_3)' [found using argument-dependent lookup]
.
.
.
c:\...\ostream(988): or 'std::basic_ostream<wchar_t,std::char_traits<wchar_t>> &std::operator <<<wchar_t,std::char_traits<wchar_t>,ns::enum_type_3>(std::basic_ostream<wchar_t,std::char_traits<wchar_t>> &&,const _Ty &)'
with
[
_Ty=ns::enum_type_3
]
while trying to match the argument list '(std::basic_ostream<wchar_t,std::char_traits<wchar_t>>, ns::enum_type_3)'
答案 0 :(得分:4)
std::ostream
是std::basic_ostream<char>
的别名。
std::wcout
的类型为std::basic_ostream<wchar_t>
,也称为std::wostream
。请注意不同的字符类型。
如果您希望operator<<
与std::wcout
一起使用,则应该选择并返回std::wostream&
而不是std::ostream&
。