Question

http://example.com/doctracklog/20140827091936

我需要从URI ff解析JSON，例如上面的示例。

内置URI（http://example.com/doctracklog/)+(textbox1)后跟textbox1; 只有textbox1的值会发生变化。

可以是Android，JavaScript等。

Answer 1

您的问题过于宽泛，但我会发布一个通用解决方案 PHP / JQUERY / JS / AJAX / .HTACCESS

文件结构

enter image description here

在文档根目录/

中创建.htaccess文件

此重写规则将使友好网址/doctracklog/{some-value}生效。

Options Indexes FollowSymLinks
RewriteEngine on
RewriteRule doctracklog/(.*)/? doctracklog.php?id=$1

在文档根目录/（JS - JQUERY - AJAX）中创建`doctracklog.php`文件

此代码将读取json对象并显示特定错误的用户信息

<!doctype html>
<html lang="en">
<head>
    <meta charset="utf-8">
    <title>Example</title>
    <!-- javascript/jQuery -->
    <script src="http://code.jquery.com/jquery-1.11.0.min.js"></script>

    <div id="holder"></div>
</head>
<body>
<script>
    $.ajax({
        url: '/json.php',
        type: 'POST',
        data: {
            'id': '<?php echo !empty($_GET['id']) ? $_GET['id'] : "";?>'
        },
        success: function (response) {
            if (response.status !== 'Error') {
                console.log(response);
                alert(response.user.name + "-" + response.user.age + "-" + response.user.gender);
            } else {
                alert(response.message);
            }
        },
        error: function () {
            alert("error");
        }
    });
</script>
</body>
</html>

在文档根目录/（PHP）

中创建json.php文件

此文件将根据传递的值（http://example.com/doctracklog/ 20140827091936 ）设置将显示哪个用户，并返回一个json对象

<?php
//this is the number you are passing in your URI. For ex. http://example.com/doctracklog/20140827091936
$userId = $_POST['id'] ? $_POST['id'] : "";

//This is a dummy array example, so we can use userId as its index
if(!empty($userId)) {
    $users = array(
        '20140827091936' => array(
            'name' => 'John',
            'age' => '20',
            'gender' => 'male'
        ),
        '20140920081120' => array(
            'name' => 'Susan',
            'age' => '32',
            'gender' => 'female'
        )
    );

    if(array_key_exists($userId,$users)) {
        $json = array('status' => 'OK', 'user' => $users[$userId]);
    } else {
        $json = array('status' => 'Error','message' => 'Id does not exist');
    }
} else {
    $json = array('status' => 'Error','message' => 'You did not pass any id');
}

//return json object
header('Content-Type: application/json');
echo json_encode($json);