Question

我在表格中有以下数据：

+----------------------+----------------------------------------------------------+--------------+
| subscriber_fields_id | name                                                     | field_type   |
+----------------------+----------------------------------------------------------+--------------+
|                  143 | Peshawar/Islamabad/Lahore/Swat/Mardan/Karachi            | Job Location |
|                  146 | Karachi                                                  | Job Location |
|                  147 | Lahore and Karachi                                       | Job Location |
|                  149 | Karachi, Mirpur Khas, Sukkur, Layyah, Gilgit, Charsaddah | Job Location |
|                  152 | Islamabad or Lahore                                      | Job Location |
|                  155 | Islamabad                                                | Job Location |
|                  157 | 7 Districts of Sindh and Karachi                         | Job Location |
+----------------------+----------------------------------------------------------+--------------+

我的查询是：

select * from subscriberfields
where  name like '%Khairpur,Islamabad,Karachi%';

结果：

+----------------------+-----------------------------------------------+--------------+
| subscriber_fields_id | name                                          | field_type   |
+----------------------+-----------------------------------------------+--------------+
|                  143 | Peshawar/Islamabad/Lahore/Swat/Mardan/Karachi | Job Location |
|                  152 | Islamabad or Lahore                           | Job Location |
|                  155 | Islamabad                                     | Job Location |
+----------------------+-----------------------------------------------+--------------+

它应该返回名称中包含Islamabad，Khairpur或Karachi的所有行，但不是。

Answer 1

要获得正确的解决方案，normalize your database design或者除此之外，请考虑full text search。

要快速解决当前问题，请使用regular expression match (~)或三个简单的LIKE表达式：

SELECT *
FROM   subscriberfields 
WHERE  name ~ '(Khairpur|Islamabad|Karachi)';

或者：

...
WHERE (name LIKE '%Khairpur%' OR
       name LIKE '%Islamabad%' OR
       name LIKE '%Karachi%')

或使用~*或ILIKE进行不区分大小写的匹配。

由于另一个答案提示：从不使用SIMILAR TO：

Answer 2

尝试使用SIMILAR TO，如下所示：

SELECT * FROM subscriberfields 
WHERE name SIMILAR TO '%(Khairpur|Islamabad|Karachi)%';

此外，您应该阅读数据库规范化。您的设计可以而且绝对应该得到改进。

Answer 3

您可以使用此：

select * from subscriberfields
where  name like any(array['%Khairpur%','%Islamabad%','%Karachi%']);

https://postgres.cz/wiki/PostgreSQL_SQL_Tricks#LIKE_to_list_of_patterns

Answer 4

在WHERE子句中使用OR，比如

select * from subscriberfields where name like '%Khairpur%' OR name like '%Islamabad%' OR name like '%Karachi%';

希望它有效。

用于匹配多个字符串之一的SQL查询

4 个答案: