这里我已经定义了我的数据 myListOfEmployeeObjects :
public class App : Application
{
public List<Employee> myListOfEmployeeObjects;
public App ()
{
Employee emp1 = new Employee () {
FirstName = "Max",
LastName = "Mustermann",
Twitter = "@fake1"
};
Employee emp2 = new Employee () {
FirstName = "Evy",
LastName = "Mustermann",
Twitter = "@fake2"
};
myListOfEmployeeObjects = new List<Employee> {
emp1, emp2
};
MainPage = new NavigationPage (new EmployeeListPage ());
}
}
比我设置ItemsSource
:
<ListView x:Name="listView"
IsVisible="false"
ItemsSource="{x:Static local:App.myListOfEmployeeObjects}"
ItemSelected="EmployeeListOnItemSelected">
这应该有用吗?因为我得到了
Xamarin.Forms.Xaml.XamlParseException:在xmlns中找不到类型的应用程序
public partial class EmployeeListPage : ContentPage {
private ListView listView;
private void InitializeComponent() {
this.LoadFromXaml(typeof(EmployeeListPage)); // here the exception is thrown
listView = this.FindByName <ListView>("listView");
}
}
如何设置我的XAML的ItemsSource
?
修改
现在我尝试了user2425632中的建议,如果我做了以下更改,它就会起作用:
xmlns:local="clr-namespace:HelloXamarinFormsWorld;assembly=HelloXamarinFormsWorld"
添加到我的XAML文件现在看起来像以下
<?xml version="1.0" encoding="UTF-8"?>
<ContentPage xmlns="http://xamarin.com/schemas/2014/forms"
xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
xmlns:local="clr-namespace:HelloXamarinFormsWorld;assembly=HelloXamarinFormsWorld"
x:Class="HelloXamarinFormsWorld.EmployeeListPage"
Title="Employee List">
<ContentPage.Content>
当然,您必须更改名称以使其适合您的项目。
我删除了IsVisible
和ItemSelected
。
<ListView ItemsSource="{x:Static local:App.myListOfEmployeeObjects}">
它必须是静态的,否则你得到
找不到本地的静态成员:App.myListOfEmployeeObjects
public static List<Employee> myListOfEmployeeObjects { private set; get; }
public static void GetAllEmployees(){
Employee emp1 = new Employee () {
FirstName = "Max",
LastName = "Mustermann",
Twitter = "@fake1"
};
Employee emp2 = new Employee () {
FirstName = "Eva",
LastName = "Mustermann",
Twitter = "@fake2"
};
myListOfEmployeeObjects = new List<Employee> {
emp1, emp2
};
}
public App ()
{
GetAllEmployees ();
MainPage = new NavigationPage (new EmployeeListPage ());
}
答案 0 :(得分:3)
所以我实际上并没有自己这样做,但是从阅读文档中我得到了一个值得你尝试的建议。
ItemsSource="{x:Static local:App.myListOfEmployeeObjects}"
在您的xaml中,您说来源是静态的但是查看您的.cs文件并不是。请尝试以下方法:
public static List<Employee> myListOfEmployeeObjects { private set; get; }
然后尝试使用静态函数设置对象,例如:
static App() {
myListOfEmployeeObjects = something;
}
然后列表应该可以在页面上查看。
我使用了以下您可能会觉得有用的链接:
Xamarin documentation on data-binding
希望有所帮助。
答案 1 :(得分:1)
我想我有解决你问题的方法。我有同样的问题,我在EmployeeListPage.xaml中添加了这一行:
xmlns:local="clr-namespace:YourNamespace;assembly=YourAssembly"
您将在项目的属性和任何page.cs中的命名空间中获取程序集的名称
答案 2 :(得分:0)
您可以使用ObservableCollections
。这种类型的集合会在对其进行更改时通知。
在您的代码中:
<强>的.cs:强>
public class YourClass : INotifyPropertyChanged //Note this INotifyPropertyChanged
{
private ObservableCollection<Employee> _myListOfEmployeeObjects;
public ObservableCollection<Employee> ObservableEmployees
{
get
{
if (_myListOfEmployeeObjects == null) LoadEmployees();
return _myListOfEmployeeObjects;
}
set
{
_myListOfEmployeeObjects = value;
OnPropertyChanged("ObservableEmployees");
}
}
private void LoadEmployees()
{
// Necessary stuff to load employees
ObservableEmployees = new ObservableCollection<Employees>();
....
}
您必须在默认构造函数中添加DataContext = this
:
public YourClass()
{
InitializeComponent();
DataContext = this;
}
然后,将必要的方法添加到NotifyOnPropertyChanged
:
protected virtual void OnPropertyChanged(string propertyName)
{
PropertyChangedEventHandler handler = PropertyChanged;
if (handler != null) handler(this, new PropertyChangedEventArgs(propertyName));
}
在.xaml中:
<ListView x:Name="listView"
IsVisible="false"
ItemsSource="{Binding Path=ObservableEmployees, ElementName=EmployeesWindow, NotifyOnSourceUpdated=True}"
ItemSelected="EmployeeListOnItemSelected">
在ElementName=EmployeesWindow
中,EmployeesWindow
是您的主窗口x:Name
。
<Window ...
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Name="EmployeesWindow" >