Question

我使用不同的密钥向NSDictionary添加数组。这是抽象：

NSMutableDictionary *myDict = [[NSMutableDictionary alloc] init];   
    for (int i = 0; i < 3; i++) {
        [myArray removeAllObjects];      
        [myArray addObject:i];
        [myArray addObject:i];   
        [myArray addObject:i];   
        [myDict setObject:myArray forKey:[NSString stringWithFormat:@“%i”, i]];
         NSLog(@"%@", myDict);
    }

这就是我得到的输出：

i = 1

“1”=（ “1”， “1”， “1”， “1” ）;

i = 2

“1”=（ “2”， “2”， “2”， “2” ）;

“2”=（ “2”， “2”， “2”， “2” ）;

i = 3

“1”=（ “3” “3” “3” “3” ）;

“2”=（ “3” “3” “3” “3” ）;

“3”=（ “3” “3” “3” “3” ）;

但如何得到这个？：

i = 3

“1”=（ “1”， “1”， “1”， “1” ）;

“2”=（ “2”， “2”， “2”， “2” ）;

“3”=（ “3” “3” “3” “3” ）;

提前感谢您的帮助。

Answer 1

您不能反复重复使用相同的数组。这样做：

NSMutableDictionary *myDict = [[NSMutableDictionary alloc] init];   
for (int i = 0; i < 3; i++) {
    NSMutableArray *myArray = [NSMutableArray array];
    [myArray addObject:@(i)];
    [myArray addObject:@(i)];   
    [myArray addObject:@(i)];   
    [myDict setObject:myArray forKey:[NSString stringWithFormat:@"%i", i]];
     NSLog(@"%@", myDict);
}

请注意，您无法将int值直接添加到数组中。请注意，您需要将它们包装为NSNumber个对象。

Answer 2

NSMutableDictionary *myDict = [[NSMutableDictionary alloc] init];
for (int i = 1; i < 4; i++) {
    NSMutableArray *myArray = [NSMutableArray arrayWithCapacity:3];
    [myArray addObject:[NSString stringWithFormat:@"%i", i]];
    [myArray addObject:[NSString stringWithFormat:@"%i", i]];
    [myArray addObject:[NSString stringWithFormat:@"%i", i]];
    [myDict setObject:myArray forKey:[NSString stringWithFormat:@"%i", i]];
    NSLog(@"%@", myDict);
}

在NSDictionary中将数组添加到不同的键

2 个答案: