Question

我真的很喜欢tooltipster，但我现在有一个问题：我将生成一个动态的项目列表，每个项目应该是一个工具提示。此工具提示的内容应该是动态的ID，我通过工具提示发送到工具提示内的页面。但是可以肯定的是，使用我当前的代码，我只是从列表的最后一个ID获取每个工具提示中的动态内容。所以，我不知道如何使用工具提示器并为每个列表项发送提示中动态内容的正确ID。

以下是我的代码：

列表项的PHP：

<script type="text/javascript">
<?php
$NoteRelativeNoteIDphpVar = $FMID;
echo "var NoteRelativeNoteIDphpVariable = 'FMRelativeID={$NoteRelativeNoteIDphpVar}';";
?>
</script>
<div id="relative<?=$RID?>" class="relativeitem">
<div id="relativeitemrelative"><?=$FMRELATIVE?></div>
<div id="relativeitemname"><?=$FMNAME?></div>
<div id="relativeitemnote"><div id="iconnamenoterelative" class="FMRelativeNote" title="LoadRelativeNote"><img src="img/icon-note.png" class="iconnamenoterelativeimg" /></div></div>
<div id="relativeitemedit"><div id="iconeditrelative" style="background-color:<?=$CATCOL?>;"><a href="forms/Achgrelative.php?aid=<?=$RID?>" title="EDIT RELATIVE OF '<?=strtoupper($ANAME)?>'" class="box"><img src="img/icon-edit.png" class="iconrelativeimg" /></a></div></div>
</div>

生成的示例 - 列表项的HTML：

<script type="text/javascript">
var NoteRelativeNoteIDphpVariable = 'FMRelativeID=23';</script>
<div id="relative1" class="relativeitem">
<div id="relativeitemrelative">Father</div>
<div id="relativeitemname">Louis</div>
<div id="relativeitemnote"><div id="iconnamenoterelative" class="FMRelativeNote" title="LoadRelativeNote"><img src="img/icon-note.png" class="iconnamenoterelativeimg" /></div></div>
<div id="relativeitemedit"><div id="iconeditrelative" style="background-color:#247ac2;"><a href="forms/Achgrelative.php?aid=1" title="EDIT RELATIVE OF 'POLLY'" class="box"><img src="img/icon-edit.png" class="iconrelativeimg" /></a></div></div>
</div>
<script type="text/javascript">
var NoteRelativeNoteIDphpVariable = 'FMRelativeID=21';</script>
<div id="relative2" class="relativeitem">
<div id="relativeitemrelative">Sister</div>
<div id="relativeitemname">Twinny</div>
<div id="relativeitemnote"><div id="iconnamenoterelative" class="FMRelativeNote" title="LoadRelativeNote"><img src="img/icon-note.png" class="iconnamenoterelativeimg" /></div></div>
<div id="relativeitemedit"><div id="iconeditrelative" style="background-color:#247ac2;"><a href="forms/Achgrelative.php?aid=2" title="EDIT RELATIVE OF 'POLLY'" class="box"><img src="img/icon-edit.png" class="iconrelativeimg" /></a></div></div>
</div>

使用过的tooltipster的JS：

$(document).ready(function() {
    $('.FMRelativeNote').tooltipster({
        theme: 'tooltipster-shadow',
        position: 'right',
        contentAsHTML: true,
        onlyOne: true,
        interactive: true,
        functionInit: function(origin, content) {

            if (content === 'LoadRelativeNote') {
                //alert(RelativeNoteID);
                // when the request has finished loading, we will change the tooltip's content
                $.ajax({
                    type: 'POST',
                    url: 'inc/FMRelativeInfo.php',
                    data: NoteRelativeNoteIDphpVariable,
                    success: function(data) {
                        origin.tooltipster('content', data);
                    }
                });

                // this returned string will overwrite the content of the tooltip for the time being
                return 'Wait while the content is loading...';
            }
            else {
                // return nothing : the initialization continues normally with its content unchanged.
            }
        }
    });
});

所以，我只需要帮助，找到将PHP列表项中的正确ID始终发送到工具提示器而不是最后一个ID的方法。

PS：你可以在截图图片中看到，内容始终是列表的最后内容，而不是不同的内容！

enter image description here

Answer 1

在工具提示者的支持下得到一点帮助，我自己找到了解决方案：

PHP：

<div id="iconnamenoterelative" class="FMRelativeNote" title="<?=$FMID?>">

HTML：

<div id="relative1" class="relativeitem">
<div id="relativeitemrelative">Father</div>
<div id="relativeitemname">Louis</div>
<div id="relativeitemnote"><div id="iconnamenoterelative" class="FMRelativeNote" title="23"><img src="img/icon-note.png" class="iconnamenoterelativeimg" /></div></div>
<div id="relativeitemedit"><div id="iconeditrelative" style="background-color:#247ac2;"><a href="forms/Achgrelative.php?aid=1" title="EDIT RELATIVE OF 'POLLY'" class="box"><img src="img/icon-edit.png" class="iconrelativeimg" /></a></div></div>
</div>
<div id="relative2" class="relativeitem">
<div id="relativeitemrelative">Sister</div>
<div id="relativeitemname">Twinny</div>
<div id="relativeitemnote"><div id="iconnamenoterelative" class="FMRelativeNote" title="21"><img src="img/icon-note.png" class="iconnamenoterelativeimg" /></div></div>
<div id="relativeitemedit"><div id="iconeditrelative" style="background-color:#247ac2;"><a href="forms/Achgrelative.php?aid=2" title="EDIT RELATIVE OF 'POLLY'" class="box"><img src="img/icon-edit.png" class="iconrelativeimg" /></a></div></div>
</div>

JS：

$(document).ready(function() {
    $('.FMRelativeNote').tooltipster({
        theme: 'tooltipster-shadow',
        position: 'right',
        contentAsHTML: true,
        onlyOne: true,
        interactive: true,
        functionInit: function(origin, content) {

            if (content != '') {
                //alert(RelativeNoteID);
                // when the request has finished loading, we will change the tooltip's content
                $.ajax({
                    type: 'POST',
                    url: 'inc/FMRelativeInfo.php',
                    data: "FMRelativeID=" + content,
                    success: function(data) {
                        origin.tooltipster('content', data);
                    }
                });

                // this returned string will overwrite the content of the  tooltip for the time being
                return 'Wait while the content is loading...';
            }
            else {
                // return nothing : the initialization continues normally with its content unchanged.
            }
        }
    });
});

谢谢你，也许它对某人也有帮助！：）

对动态内容的动态元素使用相同的tooltipster-tooltip

1 个答案: