我正在通过边做边学的方法学习Play框架。我试图制作一个简单的博客(使用官方网站上的信息)并陷入困境。
我试图制作一篇帖子的评论树。到目前为止,我设计的模型类如下:
邮政课程:
@Entity
public class Post extends Model {
@Id
public Long id;
public String title;
public Date postedAt;
@Column(columnDefinition = "TEXT")
public String content;
@OneToMany(cascade=CascadeType.ALL, fetch = FetchType.LAZY, mappedBy="post")
public List<Comment> comments;
public static Finder<Long, Post> find = new Finder(Long.class, Post.class);
public static List<Post> all() {
return find.all();
}
public static void create(Post post) {
post.save();
}
public static void delete(Long id) {
find.ref(id).delete();
}
}
评论类:
@Entity
public class Comment extends Model {
@Id
public Long id;
public String content;
public static Finder<Long, Comment> find = new Finder(Long.class, Comment.class);
public static List<Comment> all() {
return find.all();
}
public static void create(Comment comment) {
comment.save();
}
public static void delete(Long id) {
find.ref(id).delete();
}
@OneToMany(cascade=CascadeType.ALL, fetch = FetchType.LAZY, mappedBy="post")
public List<ChildComment> childComments;
@ManyToOne
public Post post;
}
ChildComment课程:
public class ChildComment extends Model{
@Id
public Long id;
public String content;
@ManyToOne
public Comment comment;
}
控制器类Application.java
public class Application extends Controller {
public static Form<Post> postForm = Form.form(Post.class);
public static Result posts() {
return ok(views.html.index.render(Post.all(), postForm));
}
public static Result index() {
return redirect(routes.Application.posts());
}
public static Result newPost() {
Form<Post> filledForm = postForm.bindFromRequest();
if (filledForm.hasErrors()) {
return badRequest(views.html.index.render(Post.all(), filledForm));
} else {
Post.create(filledForm.get());
return redirect(routes.Application.posts());
}
}
public static Result deletePost(Long id) {
Post.delete(id);
return redirect(routes.Application.posts());
}
}
我知道我必须使用一对多关系来完成任务(在模型类中,我认为我做得正确)但是我被困在实施中控制器中的逻辑来管理注释的注释和注释。任何线索或建议都会很棒。
P.S。我正在使用MySql数据库
答案 0 :(得分:1)
要创建评论,您可以这样做。
在控制器中传递帖子ID和评论数据
然后在Controller
中//post_id and commentData received from view
Post post=Post.findByPostId(post_id); //find post of that comment where findByPostId() is a function in model
Comment comment=new Comment(commentData,null,post); //Create a new Comment Object
Comment cm=Comment.save(comment); //where save() saves the Comment object in data base and return the saved object
List <Comments> allCommentsOnPost=post.getComments(); //get all comments on that post
allComments.add(cm); //add new comment to list
post.setComments(allCommentsOnPost); //set the new list in Post object
post.update(post_id); //update post entity
与保存子注释类似,从视图传递comment_id,childCommentData
//comment_id and childCommentData received from view
Comment cm=Comment.findByCommentId(comment_id); //find comment from id ,findByCommentId() defined in Comment entity
ChildComment childCom=new ChildComment(childCommentData,cm); //create new object of ChildComment
ChildComment childComment=ChildComment.save(childCom); //persist the child comment object in db ,save() is a function in model which saves ChildComment object and return it
List<ChildComments> allChildComments=cm.getChildComments(); //getting list of all the ChildComments .
allChildComments.add(childComment); //add new comment to list
cm.setChildComments(allChildComments); //set all the child comments in Comment Entity
cm.update(comment_id); //update the Comments entity in db
注意:我在两种情况下都在创建新的Comment和ChildComment对象 你也可以使用bindRequest()。get()来获取Entity对象
答案 1 :(得分:1)
实际上,您不需要为儿童使用两个课程 - 这样您只需要两个级别的评论,而只需向Comment
模型添加字段:
@ManyToOne
public Comment parent;
@OneToMany(cascade=CascadeType.ALL, fetch = FetchType.LAZY, mappedBy="parent")
public List<Comment> children;
这样你就可以在理论上拥有无限的树枝。
在创建新评论期间,您可以添加父评论的ID - 如果它为空,则表示评论位于根级别(没有父母)