Question

我有从2003年第3季度到2005年第2季度的销售员订单金额的数据，我想显示前5名销售人员的每个季度，销售人员和总订单金额的结果。

我有这个sql语句

select DATEPART (Year, [Order Date]) AS Year,
       DATEPART (QUARTER,[Order Date]) As Quarter, 
       Salesperson, 
       SUM([Order Amount]) As [Total Order Amount] 
from dbo.tbl_sales 
Group By DATEPART (YEAR, [Order Date]),  
         DATEPART (QUARTER, [Order Date]), 
         Salesperson 
Order By  SUM([Order Amount]) DESC

但不仅仅是展示前五名销售人员，请帮助。

Answer 1

我认为你每季度最多需要5个。试试这个：

select *
from (
    select
        T.Year, T.Quarter, T.Salesperson, T.[Total Order Amount],
        rank() over (partition by T.Year, T.Quarter order by T.[Total Order Amount] desc) as rnk
    from (
        select
            datepart(yy, [Order Date]) AS Year,
            datepart(qq,[Order Date]) As Quarter, 
            Salesperson, 
            sum([Order Amount]) As [Total Order Amount]
        from dbo.tbl_sales 
        group by
             datepart(yy, [Order Date]),  
             datepart(qq, [Order Date]), 
             Salesperson 
    ) as T
) as T2
where T2.rnk <= 5
order by T2.Year, T2.Quarter, T2.rnk, T2.Salesperson

我想在所有季度中排名前5位，然后突破只有少数人然后试试这个。

with top5 as (
    select Salesperson, rnk from (
        select Salesperson, rank() over (order by sum([Order Amount]) desc) as rnk
        from dbo.tbl_sales
        group by Salesperson
    ) as T
    where rnk <= 5
)
select
    datepart(yy, [Order Date]) as yr,
    datepart(qq, [Order Date]) as qtr, 
    s.Salesperson, 
    sum([Order Amount]) As [Quarterly Order Amount] 
from
    dbo.tbl_sales as s inner join
    top5 on top5.Salesperson = s.Salesperson
group by
    datepart(yy, [Order Date]),  
    datepart(qq, [Order Date]), 
    s.Salesperson 
order by
    yr,
    qtr

有助于更明确地了解您的需求。正如您所看到的那样，这两个查询是完全不同的。在查看您发布的屏幕截图后，我不确定这是您正在寻找的答案。

SQL Query比较前5名销售人员的季度结果

1 个答案: