Question

import xml.etree.ElementTree as xml

root = xml.Element('XmlToTs')
Eit = xml.Element('Eit')
root.append(Eit)


xml.SubElement(Eit, "Pid").text = "18"
Event = xml.Element("Event")
xml.SubElement(Event, "EventId").text = "12677" 
Short = xml.SubElement(Event, "ShortEventDescriptor")
xml.SubElement(Short, "Iso639LanguageCode").text = "deu" 
xml.SubElement(Short, "EventName").text = "Talk am Teich" 
xml.SubElement(Short, "Text").text = "Heute wird mit den Enten getalked" 

EID=12500
Eit.append(Event)
Eit.append(Event)
Eit.append(Event)
for EventId in Eit.iter('EventId'):
    EventId.text = str(EID)
    EID=EID+1

我希望有多个具有默认子项的“事件”节点。之后我想迭代所有并修改他们的子文本。

但是目前iter循环为所有EventIds提供12502

谢谢克里斯蒂安

Answer 1

当您致电Event = xml.Element("Event")时，您可以创建Event元素的一个实例。通过将此实例传递给.append()方法并调用它（在您的情况下为三次），ElementTree会附加三个EventId-Elments，但实际上内存中只有一个 EventId-Element。你可以用以下几行来解决这个问题：

import xml.etree.ElementTree as xml

root = xml.Element('XmlToTs')
Eit = xml.Element('Eit')
root.append(Eit)

xml.SubElement(Eit, "Pid").text = "18"

Event = xml.Element("Event")
xml.SubElement(Event, "EventId").text = "12677"
Short = xml.SubElement(Event, "ShortEventDescriptor")
xml.SubElement(Short, "Iso639LanguageCode").text = "deu" 
xml.SubElement(Short, "EventName").text = "Talk am Teich" 
xml.SubElement(Short, "Text").text = "Heute wird mit den Enten getalked" 

Eit.append(Event)
Eit.append(Event)
Eit.append(Event)

for EventId in Eit.iter('EventId'):
    print(EventId)

输出是这样的：

<ELment 'EventId' at 0x17ee170>
<ELment 'EventId' at 0x17ee170>
<ELment 'EventId' at 0x17ee170>

如您所见所有 EventId-Elements都有相同的内存加法器！

当您使用.iter()方法迭代所有EventId-Tags时，您可以在XML代码中找到ElmentTree，在每次迭代中您都要访问相同的对象，即相同 EventId-Tag。这就是为什么每个EventId-Element的所有文本属性都被分配给相同的数字12502的原因; 12500增加了两倍。

简而言之，您需要创建多个EventId实例;例如在for循环中：

for _ in range(3):
    Event = xml.Element("Event")

    xml.SubElement(Event, "EventId").text = "12677"

    Short = xml.SubElement(Event, "ShortEventDescriptor")

    xml.SubElement(Short, "Iso639LanguageCode").text = "deu" 
    xml.SubElement(Short, "EventName").text = "Talk am Teich" 
    xml.SubElement(Short, "Text").text = "Heute wird mit den Enten getalked" 

    Eit.append(Event)

之后你可以运行你的代码......

EID=12500

for EventId in Eit.iter('EventId'):
    EventId.text= str(EID)
    EID += 1

......它完美无缺！：）

完整的源代码：

import xml.etree.ElementTree as xml
from xml.dom import minidom

root = xml.Element('XmlToTs')
Eit = xml.Element('Eit')
root.append(Eit)


xml.SubElement(Eit, "Pid").text = "18"

for _ in range(3):
    Event = xml.Element("Event")

    xml.SubElement(Event, "EventId").text = "12677"

    Short = xml.SubElement(Event, "ShortEventDescriptor")

    xml.SubElement(Short, "Iso639LanguageCode").text = "deu" 
    xml.SubElement(Short, "EventName").text = "Talk am Teich" 
    xml.SubElement(Short, "Text").text = "Heute wird mit den Enten getalked" 


    Eit.append(Event)


EID=12500

for EventId in Eit.iter('EventId'):
    EventId.text= str(EID)
    EID += 1


#print the generated XML code

def prettify(elem):
    """Return a pretty-printed XML string for the Element.
    """
    rough_string = xml.tostring(elem, 'utf-8')
    reparsed = minidom.parseString(rough_string)
    return reparsed.toprettyxml(indent=" ")

print(prettify(Eit))

通过迭代插入父节点来更改子节点值

1 个答案: