目标:从Order表中选择记录,其中(delivery_date,type)不在(NULL,' A')。
select * from Orders;
Table : Orders
No Type Delivery_Date
1 A null
2 B 20150120
3 A 20150115
4 A 20150115
5 A 20150111
6 A 20150112
7 B null
8 B null
预期结果:
No Type Delivery_Date
2 B 20150120
3 A 20150115
4 A 20150115
5 A 20150111
6 A 20150112
7 B null
8 B null
在where子句中尝试了以下约束,但没有运气。
1. WHERE (DELIVERY_DATE, TYPE) IS NOT IN (NULL, 'A')
2. WHERE (NVL(DELIVERY_DATE, 0), TYPE) IS NOT IN (0, 'A')
为了使其工作,已添加名称required_row的列,如果此条件为(deliver_date为null且type =' A')并且仅选择required_row为Y的记录,则将其设置为Y.
with orders
as
(select 1 as no, 'A' as type, null as delivery_date from dual union
select 2 as no, 'B' as type, 20150120 as delivery_date from dual union
select 3 as no, 'A' as type, 20150115 as delivery_date from dual union
select 4 as no, 'A' as type, 20150115 as delivery_date from dual union
select 5 as no, 'A' as type, 20150111 as delivery_date from dual union
select 6 as no, 'A' as type, 20150112 as delivery_date from dual union
select 7 as no, 'B' as type, null as delivery_date from dual union
select 8 as no, 'B' as type, null as delivery_date from dual
)
select * from ( select orders.*,
case when orders.delivery_date is null and type = 'A'
then 'N' else 'Y'
end as required_row from orders) where required_row='Y';
任何有关在任何其他方法中实现相同目标的任何意见/想法,保持表现,将不胜感激。
答案 0 :(得分:2)
试试这个
select orders.* from orders where Delivery_Date is not null or type !='A'
/*Assuming type as a char field and this query will output all records
excluding deliverydate_null with type ='A' */
修改了上述查询以包含在小提琴中共享的sql片段。
<强>更新强>
以下是示例 SQLFIDDLE
答案 1 :(得分:1)
可以通过不存在的子查询来解决这个问题:
SELECT * FROM order t
WHERE not exists (
SELECT 1
FROM order
WHERE
type = 'A'
and delivery_date is null
and id = t.id
)