Question

在我的申请中，公司可以有很多员工，每个员工可能有多个电子邮件地址。

数据库模式将表格关联起来：

公司 - ＆gt; CompanyEmployeeXref - ＆gt;员工 - ＆gt; EmployeeAddressXref - ＆gt;电子邮件

我正在使用Entity Framework，我想创建一个LINQ查询，该查询返回公司名称和逗号分隔的员工电子邮件地址列表。这是我正在尝试的查询：


from c in Company
join ex in CompanyEmployeeXref on c.Id equals ex.CompanyId
join e in Employee on ex.EmployeeId equals e.Id
join ax in EmployeeAddressXref on e.Id equals ax.EmployeeId
join a in Address on ax.AddressId equals a.Id
select new {
              c.Name,
              a.Email.Aggregate(x=>x + ",")
           }


Desired Output:

"Company1", "a@company1.com,b@company1.com,c@company1.com"

"Company2", "a@company2.com,b@company2.com,c@company2.com"

...

我知道这段代码是错的，我想我错过了一个小组，但它说明了这一点。我不确定语法。这甚至可能吗？谢谢你的帮助。

Answer 1

现在我解决了这个问题：


from c in Company
join ex in CompanyEmployeeXref on c.Id equals ex.CompanyId
join e in Employee on ex.EmployeeId equals e.Id
join ax in EmployeeAddressXref on e.Id equals ax.EmployeeId
join a in Address on ax.AddressId equals a.Id
group a.Email by new {c.Name} into g
select new {
                Company=g.Key.Name,
                Email=g.Select(e=>e).Distinct()
            }
).ToList()
.Select(l=> 
           new {
                    l.Name,
                    Email=string.Join(",", l.Email.ToArray())
                }
        )

Answer 2

实际上很难在纯Linq to SQL（或实体框架，无论你使用哪一个）中执行此操作，因为SQL Server本身没有任何可以生成逗号分隔列表的聚合运算符，所以它没有将整个语句转换为单个查询的方法。我可以给你一个“单一陈述”Linq to SQL的答案，但它实际上不会给你很好的表现，而且我不确定它是否适用于EF。

如果您只是进行常规连接，实现结果，然后使用Linq to Objects进行连接，那会更加丑陋但更好：

var rows =
    (from c in Company
     join ex in CompanyEmployeeXref on c.Id equals ex.CompanyId
     join e in Employee on ex.EmployeeId equals e.Id
     join ax in EmployeeAddressXref on e.Id equals ax.EmployeeId
     join a in Address on ax.AddressId equals a.Id
     select new 
     {
         c.Name,
         a.Email
     }).AsEnumerable();

var emails =
    from r in rows
    group r by r.Name into g
    select new
    {
        Name = g.Key,
        Emails = g.Aggregate((x, y) => x + "," + y)
    };

Linq查询子查询为逗号分隔值

2 个答案: