Question

我是编程和堆栈溢出的新手。我选择python作为我的第一语言。今天，当我写一些代码来刷新并提高我的技能时，我写了一个小程序。但完全错误。这是程序

a = [1 , 2, 3]

def list_append():
    numbers = int(raw_input("Enter the number please")) 
    a.append(numbers)
    print a

def average(list):
    for marks in list:
        print marks
    total = float(sum(list))
    total = total / len(list)
    print ("Your total average is : %d"  %total )

def loop():
        add_numbers = raw_input("Do you want to add another number")
        if add_numbers == ("y"):
            return list_append()
        else:
            return average()

while True:
        loop()  

print average(a)

这个程序的功能基本上是要求用户输入数字。然后附加到列表，然后显示平均值，这是一个简单的。

但我希望程序在第一次输入后停止并询问用户是否要提供其他输入？

无法理解问题所在。 **我不是要求直接解决方案。我宁愿想要解释而不是解决方案本身。**

Answer 1

a = []
def average(list):
    total = float(sum(list))
    total = total / len(list)
    print ("Your total average is : %d"  %total )

while True:
    numbers = raw_input("Enter the number please or 'q' to quit : ")
    if numbers == "q":
        average(a)
        break
    else:
        a.append(int(numbers))

希望这有帮助

Answer 2

您的代码中缺少以下内容：

需要打破任何循环，你的while循环进入无限循环。

while True: loop() 2.在类型转换过程中处理异常。

numbers = int(raw_input("Enter the number please"))

在循环函数中创建用户输入数字列表并传递给list_append函数以添加数字。也可以从循环函数返回，将参数传递给average函数。

代码：

def list_append(numbers):
    while 1:
        try:
            no = int(raw_input("Enter the number please:")) 
            numbers.append(no)
            break
        except ValueError:
            print "Enter only number."
    return list(numbers)

def average(number_list):
    avg = float(sum(number_list))/ len(number_list)
    return avg

def loop():
    numbers = []
    while 1:
        add_numbers = raw_input("you want to add number in list(Y):")
        if add_numbers.lower()== ("y"):
            numbers = list_append(numbers)
        else:
            return list(numbers)

numbers = loop()  
avg = average(numbers)

print "User enter numbers:", numbers
print "average value of all enter numbers:", avg

输出：

vivek@vivek:~/Desktop/stackoverflow$ python 17.py 
you want to add number in list(Y):y
Enter the number please:10
you want to add number in list(Y):y
Enter the number please:e
Enter only number.
Enter the number please:20
you want to add number in list(Y):Y
Enter the number please:30
you want to add number in list(Y):n
User enter numbers: [10, 20, 30]
average value of all enters numbers: 20.0
vivek@vivek:~/Desktop/stackoverflow$

不要使用已经由python定义的变量名例如list

>>> list
<type 'list'>
>>> list([1,2,3])
[1, 2, 3]
>>> list = [2]
>>> list([1,2,3])
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'list' object is not callable
>>>

代码有什么问题？

2 个答案: