Question

我想从今天凌晨0点开始创建一个时间戳（明天）。任何人都可以提供一些代码，我怎么能把它作为一个字符串？

Answer 1

你有。

 NSString * yourDate = @"2015-02-13 00:00:00";   
 NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
 [dateFormat setDateFormat:@"yyyy-MM-dd HH:mm:ss"];
 NSDate * date = [dateFormat dateFromString:yourDate]; 
 NSString * timestamp = [NSString stringWithFormat:@"%f",[date timeIntervalSince1970]];

Answer 2

要在今天早上12:00到达，请使用NSCalendar获取日，月和年，然后使用这些日期组件（不包括时间）来获取NSDate：< / p>

NSDate *now = [NSDate date];
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay fromDate:now];
NSDate *thisMorning = [calendar dateFromComponents:components];

明天上午12:00，加一天：

NSDate *tomorrowMorning = [calendar dateByAddingUnit:NSCalendarUnitDay value:1 toDate:thisMorning options:0];

要将这些转换为字符串，请使用NSDateFormatter。

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
formatter.dateStyle = NSDateFormatterLongStyle;
formatter.timeStyle = NSDateFormatterLongStyle;

NSString *thisMorningString = [formatter stringFromDate:thisMorning];
NSString *tomorrowMorningString = [formatter stringFromDate:tomorrowMorning];

显然，请使用您想要的任何dateStyle和timeStyle（或dateFormat字符串）。

如果你想要自1970年以来的秒数，那就是

NSTimeInterval thisMorningIntervalSince1970 = [thisMorning timeIntervalSince1970];
NSTimeInterval tomorrowMorningIntervalSince1970 = [tomorrowMorning timeIntervalSince1970];

如果你想要那些作为字符串，它将是：

NSString *thisMorningTimeIntervalString = [NSString stringWithFormat:@"%f", thisMorningIntervalSince1970];
NSString *tomorrowMorningTimeIntervalString = [NSString stringWithFormat:@"%f", tomorrowMorningIntervalSince1970];

或者

NSString *thisMorningTimeIntervalString = [NSString stringWithFormat:@"%lld", (long long) thisMorningIntervalSince1970];
NSString *tomorrowMorningTimeIntervalString = [NSString stringWithFormat:@"%lld", (long long) tomorrowMorningIntervalSince1970];

iOS：从今天（和明天）@ 0:00:00开始的时间戳

2 个答案: