Question

@Component
@Entity
@Table(name="menu")
@Configurable
public class Menu implements Serializable{      
    ....        
    @OneToMany(mappedBy="menu", fetch=FetchType.EAGER)
    private Set<VoceMenu> voceMenuList; 

    public Set<VoceMenu> getVoceMenuList() {
        return voceMenuList;
    }

    public void setVoceMenuList(Set<VoceMenu> voceMenuList) {
        this.voceMenuList = voceMenuList;
    }
    .....   
}

我打印一个表单来编辑菜单及其相对的VoceMenu对象，这样：

<form:form action="editMenu" method="post" commandName="menu"> 
     Menu id<form:input path="id" maxlength="11"/><br/>       
     ...... 
    <c:forEach items="${menu.voceMenuList}" varStatus="counter">            
        <form:input path="voceMenuList[${counter.index}].id" maxlength="11"/>
             .....
    </c:forEach>
    <input type="submit">
</form:form>

但是，当我尝试保存对象Menu时，我收到此错误：

无效的属性＆＃39; voceMenuList [0]＆＃39; bean类[com.springgestioneerrori.model.Menu]：不能从Set of size 0获取索引为0的元素，使用属性路径＆＃; voceMenuList [0]＆＃39;

访问

Answer 1

索引无法访问Set的元素。您需要添加返回包装集合的List的方法。

@Component
@Entity
@Table(name="menu")
@Configurable
public class Menu implements Serializable{      
    ....        
    @OneToMany(mappedBy="menu", fetch=FetchType.EAGER)
    private Set<VoceMenu> voceMenus; 

    public Set<VoceMenu> getVoceMenus() {
        return voceMenus;
    }

    public void setVoceMenus(Set<VoceMenu> voceMenus) {
        this.voceMenus = voceMenus;
    }

    //bind to this
    public List<VoceMenu> getVoceMenusAsList(){
        return new ArrayList<VoceMenu>(voceMenus);
    }
    .....   
}

JSP：

<form:form action="editMenu" method="post" commandName="menu"> 
     Menu id<form:input path="id" maxlength="11"/><br/>       
     ...... 
    <c:forEach items="${menu.voceMenusAsList}" varStatus="counter">            
        <form:input path="voceMenusAsList[${counter.index}].id" maxlength="11"/>
             .....
    </c:forEach>
    <input type="submit">
</form:form>

如何在spring <form：form> </form：form>中保存许多对象

1 个答案: