我知道怎么做但我不知道的是我如何处理这样的JSON:
[{
"player": {
"id": 1,
"name": "Name",
"contact": {
"tel": "123456789",
"nick_name": "NickName"
},
"achievments": {
"achievment1": "Achievment",
"achievment2": "Achievment"
}
}
}]
"接触"和"成就"有子信息。我该如何处理?
XDocument xmlDocument = new XDocument(new XDeclaration("1.0", "utf-8", "yes"),
new XElement("Players", from player in PlayerList
select new XElement("player",
new XElement("id", player.Id),
new XElement("name", player.Name))));