Question

我正在使用Ruby on Rails 4.2，我想路由＆＃34;嵌套＆＃34;在namespace的块中使用scope :module或scope :path / resource的路径。

也就是说，我有以下路线：

resources :users, :only => [:show]

匹配

user_path    GET    /users/:id(.:format)    users#show

我想匹配以下路径

users_sessions_path         POST      /users/sessions              users/sessions#create
user_session_path           GET       /users/:id/session           users/sessions#show
delete_user_session_path    GET       /users/:id/session/delete    users/sessions#delete
user_session_path           DELETE    /users/:id/session           users/sessions#destroy

我读了official documentation，我试图说出类似

的内容

resources :users, :only => [:show] do
  scope :module => :users do
    scope :module => :sessions do 
    # scope :path => :sessions do
    # namespace :sessions do
      ...
    end
  end
end

但没有尝试成功。我应该如何陈述路线？

@dgilperez回答后

更新

我尝试了以下代码

resources :users, :only => [:show] do
  scope :module => :users do
    resource :session, :only => [:show, :new, :create, :destroy] do
      get :delete, :on => :collection, :to => 'sessions#delete' 
    end
  end
end

匹配

delete_user_session_path     GET       /users/:user_id/session/delete(.:format)    users/sessions#delete
new_user_session_path        GET       /users/:user_id/session/new(.:format)       users/sessions#new
user_session_path            POST      /users/:user_id/session(.:format)           users/sessions#create
user_session_path            GET       /users/:user_id/session(.:format)           users/sessions#show
                             DELETE    /users/:user_id/session(.:format)           users/sessions#destroy

但我仍需要映射new和create操作，而无需传递:user_id参数。也就是说，我想映射像

这样的东西

new_user_session_path        GET       /users/session/new(.:format)       users/sessions#new
user_session_path            POST      /users/session(.:format)           users/sessions#create

Answer 1

我认为你过度复杂了：你不需要使用scope或path来渲染嵌套资源。你只需嵌套它们：

resources :users, :only => [:show] do
  resources :sessions
end

将呈现以下路线：

user_sessions     GET    /users/:user_id/sessions(.:format)            sessions#index
                  POST   /users/:user_id/sessions(.:format)            sessions#create
new_user_session  GET    /users/:user_id/sessions/new(.:format)        sessions#new
edit_user_session GET    /users/:user_id/sessions/:id/edit(.:format)   sessions#edit
user_session      GET    /users/:user_id/sessions/:id(.:format)        sessions#show
                  PATCH  /users/:user_id/sessions/:id(.:format)        sessions#update
                  PUT    /users/:user_id/sessions/:id(.:format)        sessions#update
                  DELETE /users/:user_id/sessions/:id(.:format)        sessions#destroy
user              GET    /users/:id(.:format)                          users#show

这些不是您提到的路线，但我希望您重新考虑是否真的需要它们，使用命名空间控制器和自定义名称（如delete_user_）或者您更喜欢更标准。如果你真的需要这些确切的路线，请告诉我。

OP更新后

更新

要丢失两条路线，您需要将它们从休息资源中取出。我只是直接写它们：

resources :users, :only => [:show] do
  scope :module => :users do
    resource :session, :only => [:show, :destroy] do
      get :delete, :on => :collection, :to => 'sessions#delete' 
    end
  end
end

get 'users/session/new', to: 'users/sessions#new', as: :new_user_session
post 'users/session', to: 'users/sessions#create'

如何使用`namespace`或`scope：module` /`scope：path`来路由“嵌套”路径？

1 个答案: