我正在尝试使用一个计数脚本来计算45,000,但需要帮助确保最终产品有一个逗号分隔符(45,000而不是45000)。有人可以帮忙吗?
大时间提前谢谢你!
这是我的代码:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script type="text/javascript"><!--
jQuery(function($) {
$('.timer').countTo({
from: 5000,
to: 45000,
speed: 5000,
refreshInterval: 50,
onComplete: function(value) {
console.debug(this);
}
});
});
//--></script>
<h3><span class="timer" style="font-size: 7em; text-align: center;"></span></h3>
<script>
(function($) {
$.fn.countTo = function(options) {
// merge the default plugin settings with the custom options
options = $.extend({}, $.fn.countTo.defaults, options || {});
// how many times to update the value, and how much to increment the value on each update
var loops = Math.ceil(options.speed / options.refreshInterval),
increment = (options.to - options.from) / loops;
return $(this).each(function() {
var _this = this,
loopCount = 0,
value = options.from,
interval = setInterval(updateTimer, options.refreshInterval);
function updateTimer() {
value += increment;
loopCount++;
$(_this).html(value.toFixed(options.decimals));
if (typeof(options.onUpdate) == 'function') {
options.onUpdate.call(_this, value);
}
if (loopCount >= loops) {
clearInterval(interval);
value = options.to;
if (typeof(options.onComplete) == 'function') {
options.onComplete.call(_this, value);
}
}
}
});
};
$.fn.countTo.defaults = {
from: 0, // the number the element should start at
to: 100, // the number the element should end at
speed: 1000, // how long it should take to count between the target numbers
refreshInterval: 100, // how often the element should be updated
decimals: 0, // the number of decimal places to show
onUpdate: null, // callback method for every time the element is updated,
onComplete: null, // callback method for when the element finishes updating
};
})(jQuery);
答案 0 :(得分:0)
希望这个功能有所帮助:
function addCommas(nStr)
{
nStr += '';
x = nStr.split('.');
x1 = x[0];
x2 = x.length > 1 ? '.' + x[1] : '';
var rgx = /(\d+)(\d{3})/;
while (rgx.test(x1)) {
x1 = x1.replace(rgx, '$1' + ',' + '$2');
}
return x1 + x2;
}
由于